📌  相关文章
📜  Java中的 OffsetDateTime minusNanos() 方法及示例

📅  最后修改于: 2022-05-13 01:55:35.797000             🧑  作者: Mango

Java中的 OffsetDateTime minusNanos() 方法及示例

Java中 OffsetDateTime 类的minusNanos()方法返回此 OffsetDateTime 的副本,其中从解析的日期和时间中减去指定的纳秒数。

句法:

public OffsetDateTime minusNanos(long nano-seconds)

参数:此方法接受单个参数nano-seconds ,它指定要从解析日期中减去的纳秒。它也可以是负数,在这种情况下,它会增加纳秒数。

返回值:它基于此日期时间返回一个 OffsetDateTime,减去纳秒且不为空。

异常:程序在超出支持的数据和时间范围时抛出DateTimeException

下面的程序说明了minusNanos()方法:

方案一:

// Java program to demonstrate the minusNanos() method
  
import java.time.OffsetDateTime;
import java.time.ZonedDateTime;
  
public class GFG {
    public static void main(String[] args)
    {
  
        // Parses the date1
        OffsetDateTime date1
            = OffsetDateTime
                  .parse("2018-12-12T13:30:30+05:00");
  
        // Prints dates
        System.out.println("Date1: " + date1);
  
        // Subtracts the number of nano-seconds
        System.out.println("Date1 after subtracting nano-seconds: "
                           + date1.minusNanos(-120));
    }
}
输出:
Date1: 2018-12-12T13:30:30+05:00
Date1 after subtracting nano-seconds: 2018-12-12T13:30:30.000000120+05:00

方案二

// Java program to demonstrate the minusNanos() method
  
import java.time.OffsetDateTime;
import java.time.ZonedDateTime;
  
public class GFG {
    public static void main(String[] args)
    {
  
        // Parses the date1
        OffsetDateTime date1
            = OffsetDateTime
                  .parse("2018-12-12T13:30:30+05:00");
  
        // Prints dates
        System.out.println("Date1: " + date1);
  
        // Subtracts the number of nano-seconds
        System.out.println("Date1 after subtracting nano-seconds: "
                           + date1.minusNanos(140));
    }
}
输出:
Date1: 2018-12-12T13:30:30+05:00
Date1 after subtracting nano-seconds: 2018-12-12T13:30:29.999999860+05:00

参考:https: Java/time/OffsetDateTime.html#minusNanos(long)