📜  从对象列表中快速获取属性值列表 - TypeScript 代码示例
📅  最后修改于: 2022-03-11 14:48:21.202000             🧑  作者: Mango
代码示例1
let new_list = your_list.map{ $0 }
Map will transform a list of some types to a list of another types