给定整数N ,任务是找到数字的阶乘的最后两位。
例子:
Input: N = 7
Output: 40
Explanation: 7! = 5040
Input: N = 11
Output: 00
方法:我们可以观察到,对于N> = 10 ,其阶乘的最后两个位置将仅包含0。因此, N!对于任何N> = 10的%100始终为0。因此,如果N <10 ,我们只需计算阶乘并提取最后两位数。
下面是上述方法的实现:
C++
// C++ implementation to
// find last two digits
// factorial of a given number
#include
using namespace std;
// Function to print the
// last two digits of N!
void lastTwoDigits(long long N)
{
// For N >= 10, N! % 100
// will always be 0
if (N >= 10) {
cout << "00";
return;
}
long long fac = 1;
// Calculating N! % 100
for (int i = 1; i <= N; i++)
fac = (fac * i) % 100;
cout << fac;
}
// Driver code
int main()
{
int N = 7;
lastTwoDigits(N);
}
Java
// Java implementation to
// find last two digits
// factorial of a given number
import java.util.*;
class GFG{
// Function to print the
// last two digits of N!
static void lastTwoDigits(double N)
{
// For N >= 10, N! % 100
// will always be 0
if (N >= 10)
{
System.out.print("00");
return;
}
double fac = 1;
// Calculating N! % 100
for (int i = 1; i <= N; i++)
fac = (fac * i) % 100;
System.out.print(fac);
}
// Driver code
public static void main(String args[])
{
int N = 7;
lastTwoDigits(N);
}
}
// This code is contributed by Code_Mech
Python3
# Python3 implementation to
# find last two digits
# factorial of a given number
# Function to print the
# last two digits of N!
def lastTwoDigits(N):
# For N >= 10, N! % 100
# will always be 0
if (N >= 10):
print("00", end = "")
return
fac = 1
# Calculating N! % 100
for i in range(1, N + 1):
fac = (fac * i) % 100
print(fac)
# Driver code
if __name__ == '__main__':
N = 7
lastTwoDigits(N)
# This code is contributed by Mohit Kumar
C#
// C# implementation to
// find last two digits
// factorial of a given number
using System;
class GFG{
// Function to print the
// last two digits of N!
static void lastTwoDigits(double N)
{
// For N >= 10, N! % 100
// will always be 0
if (N >= 10)
{
Console.Write("00");
return;
}
double fac = 1;
// Calculating N! % 100
for (int i = 1; i <= N; i++)
fac = (fac * i) % 100;
Console.Write(fac);
}
// Driver code
public static void Main()
{
int N = 7;
lastTwoDigits(N);
}
}
// This code is contributed by Nidhi_biet
Javascript
输出:
40