Python - 按字母顺序提取具有连续字母的字符串

给定一个字符串列表，提取包含按字母顺序出现的任何连续字符的列表。

Input : test_list = [‘gfg’, ‘ij’, ‘best’, ‘for’, ‘geeks’] 
Output : [‘ij’, ‘gfg’, ‘best’] 
Explanation : i-j, f-g, s-t are consecutive pairs.

Input : test_list = [‘gf1g’, ‘in’, ‘besht’, ‘for’, ‘geeks’] 
Output : [] 
Explanation : No consecutive pairs. 

方法#1：使用 ord() + 循环

在这里，我们检查每个字符串是否包含并且字符是其前一个字符的字母后继，ASCII 转换是使用 ord() 完成的。

Python3

# Python3 code to demonstrate working of 
# Extract Strings with successive Alphabets
# Using ord() + loop
  
# initializing string list
test_list = ['gfg', 'is', 'best', 'for', 'geeks']
  
# printing original list
print("The original list is : " + str(test_list))
  
res = []
for sub in test_list:
      
    # iterating for string 
    for idx in range(len(sub) - 1):
          
        # checking for alphabetic consecution
        if ord(sub[idx]) == ord(sub[idx + 1]) - 1:
            res.append(sub)
            break
      
# printing result 
print("Strings with alphabetic consecution : " + str(res))

输出

The original list is : ['gfg', 'is', 'best', 'for', 'geeks']
Strings with alphabetic consecution : ['gfg', 'best']

方法#2：使用 any() + filter() + lambda

在这里，我们使用 any() 检查任何连续性，并使用 filter() 和 lambda函数完成过滤任务。

蟒蛇3

# Python3 code to demonstrate working of
# Extract Strings with successive Alphabets
# Using any() + filter() + lambda
  
# initializing string list
test_list = ['gfg', 'is', 'best', 'for', 'geeks']
  
# printing original list
print("The original list is : " + str(test_list))
  
# filtering using filter, and checking for any substring using any()
res = list(filter(lambda sub: any(ord(sub[idx]) == ord(
    sub[idx + 1]) - 1 for idx in range(len(sub) - 1)), test_list))
  
# printing result
print("Strings with alphabetic consecution : " + str(res))

输出

The original list is : ['gfg', 'is', 'best', 'for', 'geeks']
Strings with alphabetic consecution : ['gfg', 'best']