给定一个字符串,计算其中的辅音总数。辅音是不是元音的英语字母字符(a,e,i,o和u)。常数的示例是b,c,d,f,g 、.
例子 :
Input : abc de
Output : 3
There are three consonants b, c and d.
Input : geeksforgeeks portal
Output : 12
1.迭代方法
C++
// Iterative CPP program to count total number
// of consonants
#include
using namespace std;
// Function to check for consonant
bool isConsonant(char ch)
{
// To handle lower case
ch = toupper(ch);
return !(ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') && ch >= 65 && ch <= 90;
}
int totalConsonants(string str)
{
int count = 0;
for (int i = 0; i < str.length(); i++)
// To check is character is Consonant
if (isConsonant(str[i]))
++count;
return count;
}
// Driver code
int main()
{
string str = "abc de";
cout << totalConsonants(str);
return 0;
}
Java
// Iterative Java program
// to count total number
// of consonants
import java.io.*;
class GFG {
// Function to check for consonant
static boolean isConsonant(char ch)
{
// To handle lower case
ch = Character.toUpperCase(ch);
return !(ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') && ch >= 65 && ch <= 90;
}
static int totalConsonants(String str)
{
int count = 0;
for (int i = 0; i < str.length(); i++)
// To check is character is Consonant
if (isConsonant(str.charAt(i)))
++count;
return count;
}
// Driver code
public static void main(String args[])
{
String str = "abc de";
System.out.println( totalConsonants(str));
}
}
// This code is contributed by Nikita Tiwari.
Python3
# Iterative Python3 program to count
# total number of consonants
# Function to check for consonant
def isConsonant(ch):
# To handle lower case
ch = ch.upper()
return not (ch == 'A' or ch == 'E' or
ch == 'I' or ch == 'O' or
ch == 'U') and ord(ch) >= 65 and ord(ch) <= 90
def totalConsonants(string):
count = 0
for i in range(len(string)):
# To check is character is Consonant
if (isConsonant(string[i])):
count += 1
return count
# Driver code
string = "abc de"
print(totalConsonants(string))
# This code id contributed by Ansu Kumari.
C#
// Iterative C# program to count
// total number of consonants
using System;
class GFG {
// Function to check for consonant
static bool isConsonant(char ch)
{
// To handle lower case
ch = Char.ToUpper(ch);
return !(ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') && ch >= 65 && ch <= 90;
}
static int totalConsonants(String str)
{
int count = 0;
for (int i = 0; i < str.Length; i++)
// To check is character is Consonant
if (isConsonant(str[i]))
++count;
return count;
}
// Driver code
public static void Main()
{
String str = "abc de";
Console.Write( totalConsonants(str));
}
}
// This code is contributed by nitin mittal.
PHP
= 65 && ord($ch) <= 90;
}
function totalConsonants($str)
{
$count = 0;
for ($i = 0; $i < strlen($str); $i++)
// To check is character is Consonant
if (isConsonant($str[$i]))
++$count;
return $count;
}
// Driver code
$str = "abc de";
echo totalConsonants($str);
return 0;
// This code is contributed by Ita_c.
?>
Javascript
C++
// Recursive CPP program to count total number
// of consonants
#include
using namespace std;
// Function to check for consonant
bool isConsonant(char ch)
{
// To handle lower case
ch = toupper(ch);
return !(ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') && ch >= 65 && ch <= 90;
}
// to count total number of consonants from
// 0 to n-1
int totalConsonants(string str, int n)
{
if (n == 1)
return isConsonant(str[0]);
return totalConsonants(str, n - 1) +
isConsonant(str[n-1]);
}
// Driver code
int main()
{
string str = "abc de";
cout << totalConsonants(str, str.length());
return 0;
}
Java
// Recursive Java program to count
// total number of consonants
import java.util.*;
import java.lang.*;
class GFG
{
// Function to check for consonant
static boolean isConsonant(char ch)
{
// To handle lower case
ch = Character.toUpperCase(ch);
return (ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U')== false && ch >= 65 && ch <= 90;
}
// to count total number
// of consonants from 0 to n-1
static int totalConsonants(String str, int n)
{
if (n == 1)
{
if(isConsonant(str.charAt(0)))
return 1;
else
return 0;
}
if(isConsonant(str.charAt(n - 1)))
return totalConsonants(str, n - 1) + 1;
else
return totalConsonants(str, n - 1);
}
// Driver code
public static void main(String args[])
{
String str = "abc de";
System.out.println(totalConsonants(str, str.length()));
}
}
// This code is contributed by
// Surendra_Gangwar
Python3
# Recursive Python3 program to count
# total number of consonants
# Function to check for consonant
def isConsonant(ch):
# To handle lower case
ch = ch.upper()
return not (ch == 'A' or ch == 'E' or
ch == 'I' or ch == 'O' or
ch == 'U') and ord(ch) >= 65 and ord(ch) <= 90
# To count total number of
# consonants from 0 to n-1
def totalConsonants(string, n):
if n == 1:
return isConsonant(string[0])
return totalConsonants(string, n - 1) + isConsonant(string[n-1])
# Driver code
string = "abc de"
print(totalConsonants(string, len(string)))
# This code is contributed by Ansu Kuamri.
C#
// Recursive C# program to count
// total number of consonants
using System;
class GFG
{
// Function to check for consonant
static Boolean isConsonant(char ch)
{
// To handle lower case
ch = char.ToUpper(ch);
return (ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') == false &&
ch >= 65 && ch <= 90;
}
// to count total number
// of consonants from 0 to n-1
static int totalConsonants(String str, int n)
{
if (n == 1)
{
if(isConsonant(str[0]))
return 1;
else
return 0;
}
if(isConsonant(str[n - 1]))
return totalConsonants(str, n - 1) + 1;
else
return totalConsonants(str, n - 1);
}
// Driver code
public static void Main(String []args)
{
String str = "abc de";
Console.WriteLine(totalConsonants(str, str.Length));
}
}
// This code contributed by Rajput-Ji
Javascript
输出:
3
2.递归方法
C++
// Recursive CPP program to count total number
// of consonants
#include
using namespace std;
// Function to check for consonant
bool isConsonant(char ch)
{
// To handle lower case
ch = toupper(ch);
return !(ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') && ch >= 65 && ch <= 90;
}
// to count total number of consonants from
// 0 to n-1
int totalConsonants(string str, int n)
{
if (n == 1)
return isConsonant(str[0]);
return totalConsonants(str, n - 1) +
isConsonant(str[n-1]);
}
// Driver code
int main()
{
string str = "abc de";
cout << totalConsonants(str, str.length());
return 0;
}
Java
// Recursive Java program to count
// total number of consonants
import java.util.*;
import java.lang.*;
class GFG
{
// Function to check for consonant
static boolean isConsonant(char ch)
{
// To handle lower case
ch = Character.toUpperCase(ch);
return (ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U')== false && ch >= 65 && ch <= 90;
}
// to count total number
// of consonants from 0 to n-1
static int totalConsonants(String str, int n)
{
if (n == 1)
{
if(isConsonant(str.charAt(0)))
return 1;
else
return 0;
}
if(isConsonant(str.charAt(n - 1)))
return totalConsonants(str, n - 1) + 1;
else
return totalConsonants(str, n - 1);
}
// Driver code
public static void main(String args[])
{
String str = "abc de";
System.out.println(totalConsonants(str, str.length()));
}
}
// This code is contributed by
// Surendra_Gangwar
Python3
# Recursive Python3 program to count
# total number of consonants
# Function to check for consonant
def isConsonant(ch):
# To handle lower case
ch = ch.upper()
return not (ch == 'A' or ch == 'E' or
ch == 'I' or ch == 'O' or
ch == 'U') and ord(ch) >= 65 and ord(ch) <= 90
# To count total number of
# consonants from 0 to n-1
def totalConsonants(string, n):
if n == 1:
return isConsonant(string[0])
return totalConsonants(string, n - 1) + isConsonant(string[n-1])
# Driver code
string = "abc de"
print(totalConsonants(string, len(string)))
# This code is contributed by Ansu Kuamri.
C#
// Recursive C# program to count
// total number of consonants
using System;
class GFG
{
// Function to check for consonant
static Boolean isConsonant(char ch)
{
// To handle lower case
ch = char.ToUpper(ch);
return (ch == 'A' || ch == 'E' ||
ch == 'I' || ch == 'O' ||
ch == 'U') == false &&
ch >= 65 && ch <= 90;
}
// to count total number
// of consonants from 0 to n-1
static int totalConsonants(String str, int n)
{
if (n == 1)
{
if(isConsonant(str[0]))
return 1;
else
return 0;
}
if(isConsonant(str[n - 1]))
return totalConsonants(str, n - 1) + 1;
else
return totalConsonants(str, n - 1);
}
// Driver code
public static void Main(String []args)
{
String str = "abc de";
Console.WriteLine(totalConsonants(str, str.Length));
}
}
// This code contributed by Rajput-Ji
Java脚本
输出 :
3
递归方法的图示: