如何将给定数字转换为字符数组

给定整数N，任务是将其转换为字符数组。

例子：

Input: N = 2020 
Output: {2, 0, 2, 0} 
Explanation: Here char array arr[] = {2, 0, 2, 0}
Input: N = 12349 
Output: {1, 2, 3, 4, 9} 
Explanation: Here char array arr[] = {1, 2, 3, 4, 9}

方法：执行此操作的基本方法是递归查找N的所有数字，并将其插入所需的字符数组中。

1. 计算数字中的总位数。
2. 在数字中声明一个大小为数字的char数组。
3. 将整数分隔为数字，并将其容纳到字符数组中。
4. 在数组的每个元素中，字符“ 0”的ASCII值相加为48。

下面是上述方法的实现：

C

// C program to convert integer
// number into character array
 
#include 
#include 
 
// Function to convert integer to
// character array
char* convertIntegerToChar(int N)
{
 
    // Count digits in number N
    int m = N;
    int digit = 0;
    while (m) {
 
        // Increment number of digits
        digit++;
 
        // Truncate the last
        // digit from the number
        m /= 10;
    }
 
    // Declare char array for result
    char* arr;
 
    // Declare duplicate char array
    char arr1[digit];
 
    // Memory allocaton of array
    arr = (char*)malloc(digit);
 
    // Separating integer into digits and
    // accomodate it to character array
    int index = 0;
    while (N) {
 
        // Separate last digit from
        // the number and add ASCII
        // value of character '0' is 48
        arr1[++index] = N % 10 + '0';
 
        // Truncate the last
        // digit from the number
        N /= 10;
    }
 
    // Reverse the array for result
    int i;
    for (i = 0; i < index; i++) {
        arr[i] = arr1[index - i];
    }
 
    // Char array truncate by null
    arr[i] = '\0';
 
    // Return char array
    return (char*)arr;
}
 
// Driver Code
int main()
{
 
    // Given number
    int N = 12349;
    int len = 5;
 
    // Function call
    char* arr = convertIntegerToChar(N);
 
    // Print char array
    for (int i = 0; i < len; i++)
        printf("%c, ", arr[i]);
 
    return 0;
}

Java

// Java program to convert integer
// number into character array
class GFG{
     
// Function to convert integer to
// character array
static char[] convertIntegerToChar(int N)
{
 
    // Count digits in number N
    int m = N;
    int digit = 0;
     
    while (m > 0)
    {
         
        // Increment number of digits
        digit++;
 
        // Truncate the last
        // digit from the number
        m /= 10;
    }
 
    // Declare char array for result
    char[] arr;
 
    // Declare duplicate char array
    char []arr1 = new char[digit + 1];
 
    // Memory allocaton of array
    arr = new char[digit];
 
    // Separating integer into digits and
    // accomodate it to character array
    int index = 0;
     
    while (N > 0)
    {
         
        // Separate last digit from
        // the number and add ASCII
        // value of character '0' is 48
        arr1[++index] = (char)(N % 10 + '0');
 
        // Truncate the last
        // digit from the number
        N /= 10;
    }
 
    // Reverse the array for result
    int i;
    for(i = 0; i < index; i++)
    {
        arr[i] = arr1[index - i];
    }
 
    // Return char array
    return (char[])arr;
}
 
// Driver Code
public static void main(String[] args)
{
     
    // Given number
    int N = 12349;
    int len = 5;
 
    // Function call
    char[] arr = convertIntegerToChar(N);
 
    // Print char array
    for(int i = 0; i < len; i++)
        System.out.printf("%c, ", arr[i]);
}
}
 
// This code is contributed by amal kumar choubey

Python3

# Python3 program to convert integer
# number into character array
 
# Function to convert integer to
# character array
def convertIntegerToChar(N):
 
    # Count digits in number N
    m = N;
    digit = 0;
 
    while (m > 0):
 
        # Increment number of digits
        digit += 1;
 
        # Truncate the last
        # digit from the number
        m /= 10;   
 
    # Declare char array for result
    arr = ['0' for i in range(digit)]
 
    # Declare duplicate char array
    arr1 = ['0' for i in range(digit + 1)];
 
    # Separating integer
    # into digits and
    # accomodate it
    # to character array
    index = 0;
 
    while (N > 0):
        index += 1;
 
        # Separate last digit from
        # the number and add ASCII
        # value of character '0' is 48
        arr1[index] = chr(int(N % 10 + 48));       
 
        # Truncate the last
        # digit from the number
        N = N // 10;   
 
    # Reverse the array for result
    for i in range(0, index):
        arr[i] = arr1[index - i];   
 
    # Return char array
    return arr;
 
# Driver Code
if __name__ == '__main__':
 
    # Given number
    N = 12349;
    len = 5;
 
    # Function call
    arr = convertIntegerToChar(N);
 
    # Print array
    for i in range(0, len, 1):
        print(arr[i], end = " ");
 
# This code is contributed by gauravrajput1

C#

// C# program to convert integer
// number into character array
using System;
 
class GFG{
     
// Function to convert integer to
// character array
static char[] convertintToChar(int N)
{
 
    // Count digits in number N
    int m = N;
    int digit = 0;
     
    while (m > 0)
    {
         
        // Increment number of digits
        digit++;
 
        // Truncate the last
        // digit from the number
        m /= 10;
    }
 
    // Declare char array for result
    char[] arr;
 
    // Declare duplicate char array
    char []arr1 = new char[digit + 1];
 
    // Memory allocaton of array
    arr = new char[digit];
 
    // Separating integer into digits and
    // accomodate it to character array
    int index = 0;
     
    while (N > 0)
    {
         
        // Separate last digit from
        // the number and add ASCII
        // value of character '0' is 48
        arr1[++index] = (char)(N % 10 + '0');
 
        // Truncate the last
        // digit from the number
        N /= 10;
    }
 
    // Reverse the array for result
    int i;
    for(i = 0; i < index; i++)
    {
        arr[i] = arr1[index - i];
    }
 
    // Return char array
    return (char[])arr;
}
 
// Driver Code
public static void Main(String[] args)
{
     
    // Given number
    int N = 12349;
    int len = 5;
 
    // Function call
    char[] arr = convertintToChar(N);
 
    // Print char array
    for(int i = 0; i < len; i++)
        Console.Write("{0}, ", arr[i]);
}
}
 
// This code is contributed by amal kumar choubey

输出：

1, 2, 3, 4, 9,