Python – Tweepy 中的 API.create_mute()
Twitter是一个流行的社交网络,用户在其中分享称为推文的消息。 Twitter 允许我们使用 Twitter API 或Tweepy挖掘任何用户的数据。数据将是从用户那里提取的推文。首先要做的是从 twitter 开发人员那里轻松获得每个用户可用的消费者密钥、消费者密钥、访问密钥和访问密钥。这些密钥将帮助 API 进行身份验证。
API.create_mute()
Tweepy 模块中API
类的 create_mute create_mute()
方法用于将用户静音为认证用户。
Syntax : API.create_mute(id / screen_name / user_id)
Parameters : Only use one of the 3 options:
- id : specifies the ID or the screen name of the user.
- user_id : specifies the ID of the user, useful to differentiate accounts when a valid user ID is also a valid screen name.
- screen_name : specifies the screen name of the user, useful to differentiate accounts when a valid screen name is also a user ID.
Returns : an object of class User
示例 1:考虑以下用户:
# import the module
import tweepy
# assign the values accordingly
consumer_key = ""
consumer_secret = ""
access_token = ""
access_token_secret = ""
# authorization of consumer key and consumer secret
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
# set access to user's access key and access secret
auth.set_access_token(access_token, access_token_secret)
# calling the api
api = tweepy.API(auth)
# the screen name of the user
screen_name = "geeksforgeeks"
# muting the user
api.create_mute(screen_name)
输出 :
示例 2:通过create_mute()
方法检查用户是否已静音。
# ID of the user
id = 4802800777
print("Before using the create_mute() method : ")
if api.show_friendship(target_id = id)[0].muting == True:
print("The user has been muted by the authenticated user.")
else:
print("The user has not been muted by the authenticated user.")
# muting the user
api.create_mute(id)
print("\nAfter using the create_mute() method : ")
if api.show_friendship(target_id = id)[0].muting == True:
print("The user has been muted by the authenticated user.")
else:
print("The user has not been muted by the authenticated user.")
输出 :
Before using the create_mute() method :
The user has not been muted by the authenticated user.
After using the create_block() method :
The user has been muted by the authenticated user.
在评论中写代码?请使用 ide.geeksforgeeks.org,生成链接并在此处分享链接。