Java中的Java .util.concurrent.RecursiveAction 类与示例
RecursiveAction是一个抽象类,封装了一个不返回结果的任务。它是ForkJoinTask的子类,它是一个抽象类,表示可以在多核系统中的单独核心上执行的任务。扩展 RecursiveAction 类以创建具有void返回类型的任务。代表任务计算部分的代码保存在 RecursiveAction 的compute()方法中。
RecursiveAction 用于可拆分和并行执行的任务。这些任务不应返回任何值。例如,可以使用 RecursiveAction 轻松实现对大型数组的排序,将数组划分为可管理的小块,每个部分在单独的核心上进行排序。
类层次结构
java.lang.Object
↳ java.util.concurrent.ForkJoinTask
↳ java.util.concurrent.RecursiveAction
RecursiveAction 的构造函数:
- RecursiveAction :使用默认设置创建一个 RecursiveAction 对象。
句法:
public RecursiveAction()
方法
- compute() – 它是由任务执行计算的方法。
句法:
protected abstract void compute()
- exec() - 此方法实现了执行 RecursiveAction 任务所需的基本规则。
句法:
protected final boolean exec()
- getRawResult() – 该函数返回任务完成状态。它总是返回 null。
句法:
public final Void getRawResult()
- setRawResult() – 该函数将任务完成状态设置为参数中传递的值。
句法:
protected final void setRawResult(Void mustBeNull)
示例:演示 RecursiveAction 类
// Java program to demonstrate RecursiveAction Class
import java.util.concurrent.ForkJoinPool;
import java.util.concurrent.RecursiveAction;
public class ForkJoinDemo {
public static void main(String[] args)
{
// Create a pool of threads.
ForkJoinPool fjp = new ForkJoinPool();
double[] nums = new double[100000];
// Give nums some values
for (int i = 0; i < nums.length; i++) {
nums[i] = (double)i;
}
System.out.println("A portion of the original sequence");
for (int i = 0; i < 9; i++) {
System.out.print(nums[i] + " ");
}
System.out.println();
SqrtTransform task
= new SqrtTransform(nums, 0, nums.length);
// Start the task
fjp.invoke(task);
System.out.println("A portion of the transformed sequence"
+ " (to four decimal places): ");
for (int i = 0; i < 9; i++) {
System.out.printf("%.4f ", nums[i]);
}
System.out.println();
}
}
// A task that transforms the elements into their square roots
class SqrtTransform extends RecursiveAction {
final int seqThreshold = 1000;
double[] data;
// Determines what part of data to process
int start, end;
SqrtTransform(double[] data, int start, int end)
{
this.data = data;
this.start = start;
this.end = end;
}
// The method where parallel computation will occur
@Override
protected void compute()
{
// If the number of elements are less
// than the sequential threshold
if ((end - start) < seqThreshold) {
for (int i = start; i < end; i++) {
data[i] = Math.sqrt(data[i]);
}
}
else {
// Otherwise, continue to break the data into smaller pieces
// Find the midpoint
int middle = (start + end) / 2;
// Invoke new tasks, using the subdivided tasks.
invokeAll(new SqrtTransform(data, start, middle),
new SqrtTransform(data, middle, end));
}
}
}
输出:
A portion of the original sequence
0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0
A portion of the transformed sequence (to four decimal places):
0.0000 1.0000 1.4142 1.7321 2.0000 2.2361 2.4495 2.6458 2.8284
参考: https: Java/util/concurrent/RecursiveAction.html