📜  spigot start.bat 代码 - Java (1)

📅  最后修改于: 2023-12-03 15:35:02.527000             🧑  作者: Mango

Spigot Start.bat Code - Java

This is a start.bat code written in Java for Spigot. It's used to launch a Spigot server.

Code
@echo off
title Spigot Server
java -Xms1G -Xmx1G -jar spigot-1.16.5.jar
pause
Instructions
  1. Copy the code above into a new text file.
  2. Save the file as "start.bat" in the same folder as your Spigot jar file.
  3. Make sure the jar file and start.bat file have the same name.
  4. Double click the start.bat file to launch the Spigot server.
Explanation
  • @echo off - This command hides the command prompt window while the server is running.
  • title Spigot Server - This command sets the title of the command prompt window to "Spigot Server".
  • java -Xms1G -Xmx1G -jar spigot-1.16.5.jar - This command launches the server with 1GB of RAM allocated to it.
  • pause - This command pauses the command prompt window so you can see any errors that occur when launching the server.
Conclusion

This start.bat code is a simple and easy way to launch a Spigot server. By following the instructions above, you should be able to get your server up and running in no time!