C | 运营商问题8

问题描述

设计一个程序，根据给定的手机号码，判断该号码属于哪家运营商。

输入

一个长度为11位的数字字符串，表示手机号码。

输出

一个字符串，表示该手机号码的运营商名称。

运营商列表

以下是几家常见的运营商及其号段：

• 移动：138, 139, 136, 137, 150, 151, 152, 157, 158, 159, 182, 183, 184, 187, 188, 147, 178, 1705
• 联通：130, 131, 132, 155, 156, 185, 186, 145, 176, 1709
• 电信：133, 153, 180, 181, 189, 177, 1700

示例

输入：

"13812345678"

输出：

"移动"

解题思路

我们可以根据手机号码的前几位数字进行匹配，判断其属于哪个运营商。

代码实现

下面是一个简单的 C 代码示例实现：

#include <stdio.h>
#include <string.h>

const char* getOperator(const char* phoneNumber) {
    // 移动
    if (strncmp(phoneNumber, "138", 3) == 0 ||
        strncmp(phoneNumber, "139", 3) == 0 ||
        strncmp(phoneNumber, "136", 3) == 0 ||
        strncmp(phoneNumber, "137", 3) == 0 ||
        strncmp(phoneNumber, "150", 3) == 0 ||
        strncmp(phoneNumber, "151", 3) == 0 ||
        strncmp(phoneNumber, "152", 3) == 0 ||
        strncmp(phoneNumber, "157", 3) == 0 ||
        strncmp(phoneNumber, "158", 3) == 0 ||
        strncmp(phoneNumber, "159", 3) == 0 ||
        strncmp(phoneNumber, "182", 3) == 0 ||
        strncmp(phoneNumber, "183", 3) == 0 ||
        strncmp(phoneNumber, "184", 3) == 0 ||
        strncmp(phoneNumber, "187", 3) == 0 ||
        strncmp(phoneNumber, "188", 3) == 0 ||
        strncmp(phoneNumber, "147", 3) == 0 ||
        strncmp(phoneNumber, "178", 3) == 0 ||
        strncmp(phoneNumber, "1705", 4) == 0)
    {
        return "移动";
    }
    // 联通
    else if (strncmp(phoneNumber, "130", 3) == 0 ||
             strncmp(phoneNumber, "131", 3) == 0 ||
             strncmp(phoneNumber, "132", 3) == 0 ||
             strncmp(phoneNumber, "155", 3) == 0 ||
             strncmp(phoneNumber, "156", 3) == 0 ||
             strncmp(phoneNumber, "185", 3) == 0 ||
             strncmp(phoneNumber, "186", 3) == 0 ||
             strncmp(phoneNumber, "145", 3) == 0 ||
             strncmp(phoneNumber, "176", 3) == 0 ||
             strncmp(phoneNumber, "1709", 4) == 0)
    {
        return "联通";
    }
    // 电信
    else if (strncmp(phoneNumber, "133", 3) == 0 ||
             strncmp(phoneNumber, "153", 3) == 0 ||
             strncmp(phoneNumber, "180", 3) == 0 ||
             strncmp(phoneNumber, "181", 3) == 0 ||
             strncmp(phoneNumber, "189", 3) == 0 ||
             strncmp(phoneNumber, "177", 3) == 0 ||
             strncmp(phoneNumber, "1700", 4) == 0)
    {
        return "电信";
    }
    else {
        return "未知运营商";
    }
}

int main() {
    const char* phoneNumber = "13812345678";
    const char* operator = getOperator(phoneNumber);
    printf("%s\n", operator);
    return 0;
}

以上代码通过比较手机号码的前几位数字，来判断其属于哪个运营商，并返回对应的运营商名称。

注意：此示例代码仅给出了一种实现思路，实际运营商号段可能会发生变化，具体实现需要根据实际情况进行调整。