📅  最后修改于: 2023-12-03 14:59:47.531000             🧑  作者: Mango
uint8_t
is a data type in C++ programming language. It is defined in the stdint.h
header file, which provides typedefs for exact-width integer types.
uint8_t
is an unsigned 8-bit integer type. It represents values between 0 and 255 inclusively. This data type provides exact-width guarantees, which means that it is guaranteed to be 8 bits wide on any platform.
To use uint8_t
, you have to include the stdint.h
header file. This header file is part of the C++ Standard Library and should be available on any compliant C++ compiler.
#include <stdint.h>
uint8_t myByte = 255;
In the example above, we declare a variable called myByte
and initialize it with the value 255
. Since myByte
is of type uint8_t
, it can store values between 0 and 255 inclusively.
By using uint8_t
instead of unsigned char
, you ensure that the integer type has a guaranteed size of 8 bits. This is especially important when working with systems that have specific requirements for data types.
Additionally, uint8_t
has a clearly defined range of values, which can help to prevent overflow and underflow errors.
In this article, we introduced uint8_t
- an unsigned 8-bit integer type in C++. We discussed how to use it and its benefits over other integer types.