Python - 过滤没有空格字符串的行
给定 Matrix，提取字符串中没有空格的行。
例子：
Input : test_list = [[“gfg is”, “best”], [“gfg”, “good”], [“gfg is cool”], [“love”, “gfg”]]
Output : [[‘gfg’, ‘good’], [‘love’, ‘gfg’]]
Explanation : Both the lists have strings don’t have spaces.
Input : test_list = [[“gfg is”, “best”], [“gfg “, “good”], [“gfg is cool”], [“love”, “gfg”]]
Output : [[‘love’, ‘gfg’]]
Explanation : List has strings don’t have spaces.
方法 #1：使用列表理解+ any() + regex
在这里，我们使用正则表达式检查每个字符串中是否没有空格，any() 用于检查发现的任何带有空格的字符串，不添加该行。
Python3
# Python3 code to demonstrate working of
# Filter rows without Space Strings
# Using list comprehension + any() + regex
import re
# initializing list
test_list = [["gfg is", "best"], ["gfg", "good"],
["gfg is cool"], ["love", "gfg"]]
# printing original list
print("The original list is : " + str(test_list))
# checking for spaces using regex
# not including row if any string has space
res = [row for row in test_list if not any(
bool(re.search(r"\s", ele)) for ele in row)]
# printing result
print("Filtered Rows : " + str(res))Python3
# Python3 code to demonstrate working of
# Filter rows without Space Strings
# Using filter() + lambda + any() + regex
import re
# initializing list
test_list = [["gfg is", "best"], ["gfg", "good"],
["gfg is cool"], ["love", "gfg"]]
# printing original list
print("The original list is : " + str(test_list))
# checking for spaces using regex
# not including row if any string has space
res = list(filter(lambda row: not any(bool(re.search(r"\s", ele))
for ele in row), test_list))
# printing result
print("Filtered Rows : " + str(res))输出：
The original list is : [[‘gfg is’, ‘best’], [‘gfg’, ‘good’], [‘gfg is cool’], [‘love’, ‘gfg’]]
Filtered Rows : [[‘gfg’, ‘good’], [‘love’, ‘gfg’]]
方法 #2：使用filter() + lambda + any() + regex
在此，我们使用 filter() 和 lambda函数执行过滤任务，其余所有功能都与上述方法类似。
蟒蛇3
# Python3 code to demonstrate working of
# Filter rows without Space Strings
# Using filter() + lambda + any() + regex
import re
# initializing list
test_list = [["gfg is", "best"], ["gfg", "good"],
["gfg is cool"], ["love", "gfg"]]
# printing original list
print("The original list is : " + str(test_list))
# checking for spaces using regex
# not including row if any string has space
res = list(filter(lambda row: not any(bool(re.search(r"\s", ele))
for ele in row), test_list))
# printing result
print("Filtered Rows : " + str(res))
输出：
The original list is : [[‘gfg is’, ‘best’], [‘gfg’, ‘good’], [‘gfg is cool’], [‘love’, ‘gfg’]]
Filtered Rows : [[‘gfg’, ‘good’], [‘love’, ‘gfg’]]