红宝石 |日期格里高利？函数

Date#gregorian?()是一个 Date 类方法，用于检查日期是否在日历改革之日或之后。

Syntax: Date.gregorian?()

Parameter: Date values

Return: true – if the date is on or after the day of calendar reform otherwise return false.

示例 #1：

# Ruby code for Date.gregorian?() method
  
# loading date
require 'date'
  
# declaring Date 
a = Date.new(2019, 1, 1)
  
# declaring Date
b = Date.jd(2452004)
  
# declaring Date
c = Date.ordinal(2019, 12)
  
# Date 
puts "Date a : #{a}\n\n"
puts "Date b : #{b}\n\n"
puts "Date c : #{c}\n\n\n\n"
  
  
# gregorian? form 
puts "Date a gregorian? form : #{a.gregorian?}\n\n"
puts "Date b gregorian? form : #{b.gregorian?}\n\n"
puts "Date c gregorian? form : #{c.gregorian?}\n\n"

输出 ：

Date a : 2019-01-01

Date b : 2001-04-04

Date c : 2019-01-12



Date a gregorian? form : true

Date b gregorian? form : true

Date c gregorian? form : true

示例 #2：

# Ruby code for Date.gregorian?() method
  
# loading date
require 'date'
  
# declaring Date 
a = Date.parse('2019-01-01')
  
# declaring Date
b = Date.strptime('03-12-2019', '%d-%m-%Y')
  
# declaring Date
c = Date.commercial(2019, 5, 6)
  
# Date 
puts "Date a : #{a}\n\n"
puts "Date b : #{b}\n\n"
puts "Date c : #{c}\n\n\n\n"
  
  
# gregorian? form 
puts "Date a gregorian? form : #{a.gregorian?}\n\n"
puts "Date b gregorian? form : #{b.gregorian?}\n\n"
puts "Date c gregorian? form : #{c.gregorian?}\n\n"

输出 ：

Date a : 2019-01-01

Date b : 2019-12-03

Date c : 2019-02-02



Date a gregorian? form : true

Date b gregorian? form : true

Date c gregorian? form : true