Python程序检查字典的值是否与列表中的顺序相同

给定一个字典，测试值是否与列表值按顺序排列。

Input : test_dict = {“gfg” : 4, “is” : 10, “best” : 11}, sub_list = [4, 10, 11] 
Output : True 
Explanation : Values are 4, 10, 11, same as list order. Hence True is returned.
 

Input : test_dict = {“gfg” : 4, “is” : 10, “best” : 11}, sub_list = [4, 11, 10] 
Output : False 
Explanation : Values are 4, 10, 11, list order is 4, 11, 10, not same order. Hence False is returned. 

方法#1：使用循环

在这种情况下，我们迭代字典值和列表，并测试所有值是否有序，如果任何元素无序，则标记关闭。

Python3

# Python3 code to demonstrate working of 
# Test for Ordered values from List
# Using loop
  
# initializing dictionary
test_dict = {"gfg" : 4, "is" : 10, "best" : 11, "for" : 19, "geeks" : 1}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing list 
sub_list = [4, 10, 11, 19, 1]
  
idx = 0
res = True
for key in test_dict:
      
    # checking for inequality in order
    if test_dict[key] != sub_list[idx]:
        res = False
        break
    idx += 1
      
# printing result 
print("Are values in order : " + str(res))

输出：

The original dictionary is : {‘gfg’: 4, ‘is’: 10, ‘best’: 11, ‘for’: 19, ‘geeks’: 1}
Are values in order : True

方法#2：使用values( ) +比较运算符

在这里，我们使用 values() 提取所有值，然后使用运算符来检查与列表的相等性。

蟒蛇3

# Python3 code to demonstrate working of 
# Test for Ordered values from List
# Using values() + comparison operators
  
# initializing dictionary
test_dict = {"gfg" : 4, "is" : 10, "best" : 11, "for" : 19, "geeks" : 1}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing list 
sub_list = [4, 10, 11, 19, 1]
  
# comparing values with list
res = list(test_dict.values()) == sub_list
      
# printing result 
print("Are values in order : " + str(res)) 

输出：

The original dictionary is : {‘gfg’: 4, ‘is’: 10, ‘best’: 11, ‘for’: 19, ‘geeks’: 1}
Are values in order : True