Python程序将字典及其键分成K个相等的字典
给定一个字典，通过划分每个键的值，将其划分为大小为 k 的相等字典列表。
Input : test_dict = {“Gfg” : 9, “is” : 6, “best” : 12} , K = 3
Output : [{‘Gfg’: 3.0, ‘is’: 2.0, ‘best’: 4.0}, {‘Gfg’: 3.0, ‘is’: 2.0, ‘best’: 4.0}, {‘Gfg’: 3.0, ‘is’: 2.0, ‘best’: 4.0}]
Explanation : Values distributed equally among dictionaries.
Input : test_dict = {“Gfg” : 6, “is” : 4, “best” : 2} , K = 2
Output : [{‘Gfg’: 3.0, ‘is’: 2.0, ‘best’: 1.0}, {‘Gfg’: 3.0, ‘is’: 2.0, ‘best’: 1.0}]
Explanation : Values distributed equally among dictionaries.
方法#1：使用循环
这是可以执行此任务的方法之一。在此，我们计算每个所需键的值并将每个字典附加到字典列表中。
Python3
# Python3 code to demonstrate working of
# Divide dictionary into K equal dictionaries
# Using loop
# initializing dictionary
test_dict = {"Gfg": 20, "is": 36, "best": 100}
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
# initializing size
K = 4
# constructing new dict
temp = dict()
for key in test_dict:
temp[key] = test_dict[key] / 4
# creating list
res = []
for idx in range(K):
res.append(temp)
# printing result
print("Required dictionary list : " + str(res))Python3
# Python3 code to demonstrate working of
# Divide dictionary into K equal dictionaries
# Using dictionary comprehension + list comprehension
# function to divide dictionary
# and keys into K equal dictionaries
def divideDictKeys(dictionary, K):
# constructing new dict
# using dictionary comprehension
temp = {key: test_dict[key] / K for key in test_dict}
# creating list
# using list comprehension
res = [temp for idx in range(K)]
return str(res)
# driver code
# initializing dictionary
test_dict = {"Gfg": 20, "is": 36, "best": 100}
# initializing size
K = 4
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
# printing result
print("Required dictionary list : " + divideDictKeys(test_dict, K))输出：
The original dictionary is : {‘Gfg’: 20, ‘is’: 36, ‘best’: 100}
Required dictionary list : [{‘Gfg’: 5.0, ‘is’: 9.0, ‘best’: 25.0}, {‘Gfg’: 5.0, ‘is’: 9.0, ‘best’: 25.0}, {‘Gfg’: 5.0, ‘is’: 9.0, ‘best’: 25.0}, {‘Gfg’: 5.0, ‘is’: 9.0, ‘best’: 25.0}]
方法#2：使用字典理解+列表理解
这是可以执行此任务的另一种方式。在这里，我们使用字典理解形成字典，使用列表理解作为简写列表来解决这个问题。
蟒蛇3
# Python3 code to demonstrate working of
# Divide dictionary into K equal dictionaries
# Using dictionary comprehension + list comprehension
# function to divide dictionary
# and keys into K equal dictionaries
def divideDictKeys(dictionary, K):
# constructing new dict
# using dictionary comprehension
temp = {key: test_dict[key] / K for key in test_dict}
# creating list
# using list comprehension
res = [temp for idx in range(K)]
return str(res)
# driver code
# initializing dictionary
test_dict = {"Gfg": 20, "is": 36, "best": 100}
# initializing size
K = 4
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
# printing result
print("Required dictionary list : " + divideDictKeys(test_dict, K))
输出：
The original dictionary is : {‘Gfg’: 20, ‘is’: 36, ‘best’: 100}
Required dictionary list : [{‘Gfg’: 5.0, ‘is’: 9.0, ‘best’: 25.0}, {‘Gfg’: 5.0, ‘is’: 9.0, ‘best’: 25.0}, {‘Gfg’: 5.0, ‘is’: 9.0, ‘best’: 25.0}, {‘Gfg’: 5.0, ‘is’: 9.0, ‘best’: 25.0}]