Python - 用有序值过滤字典

给定字典列表，任务是编写一个Python程序来过滤字典，其中的值按升序排列，即排序。

例子：

Input : test_list = [{‘gfg’ : 2, ‘is’ : 8, ‘good’ : 10}, {‘gfg’ : 1, ‘for’ : 10, ‘geeks’ : 9}, {‘love’ : 3, ‘gfg’ : 4}] 
Output : [{‘gfg’: 2, ‘is’: 8, ‘good’: 10}, {‘love’: 3, ‘gfg’: 4}] 
Explanation : 2, 8, 10 are in increasing order.
 

Input : test_list = [{‘gfg’ : 2, ‘is’ : 8, ‘good’ : 10}, {‘gfg’ : 1, ‘for’ : 10, ‘geeks’ : 9}, {‘love’ : 4, ‘gfg’ : 3}] 
Output : [{‘gfg’: 2, ‘is’: 8, ‘good’: 10}] 
Explanation : 2, 8, 10 are in increasing order. 

方法 #1：使用sorted() + values() +列表理解

在这里，我们使用 sorted() 执行排序任务并使用 values() 提取值，列表理解用于执行所有字典的迭代。

Python3

# Python3 code to demonstrate working of
# Filter dictionaries with ordered values
# Using sorted() + values() + list comprehension
  
# initializing list
test_list = [{'gfg': 2, 'is': 8, 'good': 10},
             {'gfg': 1, 'for': 10, 'geeks': 9},
             {'love': 3, 'gfg': 4}]
  
# printing original list
print("The original list is : " + str(test_list))
  
# sorted to check with ordered values
# values() extracting dictionary values
res = [sub for sub in test_list if sorted(
    list(sub.values())) == list(sub.values())]
  
# printing result
print("The filtered Dictionaries : " + str(res))

输出：

The original list is : [{‘gfg’: 2, ‘is’: 8, ‘good’: 10}, {‘gfg’: 1, ‘for’: 10, ‘geeks’: 9}, {‘love’: 3, ‘gfg’: 4}]
The filtered Dictionaries : [{‘gfg’: 2, ‘is’: 8, ‘good’: 10}, {‘love’: 3, ‘gfg’: 4}]

方法 #2：使用filter() + lambda + sorted()

在这里，我们使用 filter() 执行过滤任务，并且 lambda函数用于执行注入检查增加值所需的功能的任务。

蟒蛇3

# Python3 code to demonstrate working of
# Filter dictionaries with ordered values
# Using filter() + lambda + sorted()
  
# initializing list
test_list = [{'gfg': 2, 'is': 8, 'good': 10},
             {'gfg': 1, 'for': 10, 'geeks': 9},
             {'love': 3, 'gfg': 4}]
  
# printing original list
print("The original list is : " + str(test_list))
  
# sorted to check with ordered values
# values() extracting dictionary values
# filter() and lambda function used to filter
res = list(filter(lambda sub: sorted(list(sub.values()))
                  == list(sub.values()), test_list))
  
# printing result
print("The filtered Dictionaries : " + str(res))

输出：

The original list is : [{‘gfg’: 2, ‘is’: 8, ‘good’: 10}, {‘gfg’: 1, ‘for’: 10, ‘geeks’: 9}, {‘love’: 3, ‘gfg’: 4}]
The filtered Dictionaries : [{‘gfg’: 2, ‘is’: 8, ‘good’: 10}, {‘love’: 3, ‘gfg’: 4}]