Python中的 hex()函数

hex()函数是 Python3 中的内置函数之一，用于将整数转换为对应的十六进制形式。

句法 ：

hex(x) 
Parameters : 
x - an integer number (int object)
Returns :  Returns hexadecimal string.

错误和异常：

TypeError :  Returns TypeError when anything other than
             integer type constants are passed as parameters.

代码 #1：说明hex()函数的使用。

Python3

# Python3 program to illustrate
# hex() function
 
print("The hexadecimal form of 23 is "
                            + hex(23))
                             
print("The hexadecimal form of the "
      "ascii value is 'a' is " + hex(ord('a')))
       
print("The hexadecimal form of 3.9 is "
                        + float.hex(3.9))

输出 ：

The hexadecimal form of 23 is 0x17
The hexadecimal form of the ascii value os 'a' is 0x61
The hexadecimal form of 3.9 is 0x1.f333333333333p+1

代码 #2：当浮点值作为参数传递时演示 TypeError。

Python3

# hex() accepts only integer values as parameters
print("The hexadecimal form of 11.1 is "
                            + hex(11.1))
 
'''
# The hexadecimal conversion of floating 
# point integers can be done using the
# function float.hex()
print("The hexadecimal form of 11.1 is "
                    + float.hex(11.1))
# Output :
# The hexadecimal form of 11.1 is 0x1.6333333333333p+3
 
# Similarly, float.hex() throws a TypeError
# when integer values are passed in it.
'''

输出 ：

Traceback (most recent call last):
  File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in 
    print("The hexadecimal form of 11.1 is "+hex(11.1))
TypeError: 'float' object cannot be interpreted as an integer

应用：
hex() 用于所有标准转换。例如十六进制到十进制的转换，十六进制到八进制的转换，十六进制到二进制的转换。

代码#3：

Python3

# TypeConversion from decimal with base 10
# to hexadecimal form with base 16
 
 
# Taking input from user
# an integer with base 10
number = int(input("Enter a number with base 10\n"))
 
# The choices present to the user
print("a. Decimal to Hexadecimal ")
print("b. Decimal to Octal")
print("c. Decimal to Binary")
 
# taking user input
print("Enter your choice :- ")
choice = input()
 
# Running a variable choice
# Hexadecimal form if choice
# is set to 'a'
if choice is 'a':
 
    # lstrip helps remove "0x" from the left
    # rstrip helps remove "L" from the right,
    # L represents a long number
    print("Hexadecimal form of " + str(number) +
        " is " + hex(number).lstrip("0x").rstrip("L"))
         
if choice is 'b':
     
    # Octal representation is done
    # by adding a prefix "0o"
    print("Octal form of " + str(number) +
        " is " + oct(number).lstrip("0o").rstrip("L"))
         
if choice is 'c':
     
    # Binary representation is done by
    # the addition of prefix "0b"
    print("Binary form of " + str(number) +
        " is "+bin(number).lstrip("0b").rstrip("L"))

输出 ：

输入变量 a)

Enter a number with base 10
123
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice:- 
a
Hexadecimal form of 123 is 7b

输入变量 b)

Enter a number with base 10
123456789
a. Decimal to Hexadecimal 
b. Decimal to Octal
c. Decimal to Binary
Enter your choice:- 
a
Hexadecimal form of 123456789 is 75bcd15