PyQt5 QSpinBox - 检查它是否是活动窗口

在本文中，我们将了解如何检查旋转框是否为活动窗口。活动窗口是包含具有键盘焦点的小部件的窗口（如果该窗口没有小部件或没有任何小部件接受键盘焦点，则该窗口可能仍具有焦点）。默认情况下，此属性为 false。

为了做到这一点，我们使用带有旋转框对象的isActiveWindow方法。

Syntax : spin_box.isActiveWindow()

Argument : It takes no argument

Return : It returns bool

下面是实现

# importing libraries
from PyQt5.QtWidgets import * 
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import * 
from PyQt5.QtCore import * 
import sys
  
  
class Window(QMainWindow):
  
    def __init__(self):
        super().__init__()
  
        # setting title
        self.setWindowTitle("Python ")
  
        # setting geometry
        self.setGeometry(100, 100, 600, 400)
  
        # calling method
        self.UiComponents()
  
        # showing all the widgets
        self.show()
  
        # method for widgets
    def UiComponents(self):
        # creating spin box
        self.spin = QSpinBox(self)
  
        # setting geometry to spin box
        self.spin.setGeometry(100, 100, 250, 40)
  
        # setting range to the spin box
        self.spin.setRange(1, 999999)
  
        # setting prefix to spin
        self.spin.setPrefix("PREFIX ")
  
        # setting suffix to spin
        self.spin.setSuffix(" SUFFIX")
  
        # creating a label
        label = QLabel(self)
  
        # making the label multi line
        label.setWordWrap(True)
  
        # setting geometry to the label
        label.setGeometry(100, 200, 200, 60)
  
        # checking if spin box is active window
        check = self.spin.isActiveWindow()
  
        # setting text to the label
        label.setText("Active window? : " + str(check))
  
  
# create pyqt5 app
App = QApplication(sys.argv)
  
# create the instance of our Window
window = Window()
  
# start the app
sys.exit(App.exec())

输出 ：