📜  ajax 获取请求参数 - Javascript 代码示例

📅  最后修改于: 2022-03-11 15:03:26.379000             🧑  作者: Mango

代码示例1
$.ajax({
    url: "ajax.aspx?ajaxid=4&UserID=" + UserID + "&EmailAddress=" + encodeURIComponent(EmailAddress),
    success: function(response) {
        //Do Something
    },
    error: function(xhr) {
        //Do Something to handle error
    }
});