📜  PHPUnit assertNull()函数

📅  最后修改于: 2022-05-13 01:56:40.935000             🧑  作者: Mango

PHPUnit assertNull()函数

assertNull()函数是 PHPUnit 中的内置函数,用于断言变量是否为 Null。如果变量为 Null,则此断言将返回 true,否则返回 false。如果为真,则断言的测试用例通过,否则测试用例失败。

句法:

assertNull(mixed $variable[, string $message = ''])

参数:该函数接受上面提到的两个参数,如下所述:

  • $Variable:这个参数代表任何类型的变量。
  • $message:此参数采用字符串值。当测试用例失败时,此字符串消息显示为错误消息。

下面的例子说明了 PHPUnit 中的 assertNull()函数:

示例 1:

PHP
assertNull( 
            $variable, 
            "variable is null or not"
        ); 
    } 
} 
    
?>


PHP
assertNull( 
            $variable, 
            "variable is null or not"
        ); 
    } 
} 
    
?>


输出:

PHPUnit 8.5.8 by Sebastian Bergmann and contributors.

F                                                  1 / 1 (100%)

Time: 88 ms, Memory: 10.00 MB

There was 1 failure:

1) GeeksPhpunitTestCase::testPositiveTestcaseForassertNull
variable is null or not
Failed asserting that 'Null' is null.

/home/lovely/Documents/php/test.php:15

FAILURES!
Tests: 1, Assertions: 1, Failures: 1.

示例 2:

PHP

assertNull( 
            $variable, 
            "variable is null or not"
        ); 
    } 
} 
    
?> 

输出:

PHPUnit 8.5.8 by Sebastian Bergmann and contributors.

.                                                 1 / 1 (100%)

Time: 88 ms, Memory: 10.00 MB

OK (1 test, 1 assertion)

参考: https://phpunit.readthedocs.io/en/9.2/assertions.html#assertnull