📅  最后修改于: 2022-03-11 14:47:21.847000             🧑  作者: Mango
# True since 1,3 and 4 (at least one) is true
l = [1, 3, 4, 0]
print(any(l))
# False since both are False
l = [0, False]
print(any(l))
# True since 5 is true
l = [0, False, 5]
print(any(l))