Java中的 CompositeName startsWith() 方法和示例
javax.naming.CompositeName 类的startsWith()方法用于检查作为参数传递的复合名称是否是该复合名称的前缀。如果该复合名称对象以“X”结尾,则复合名称“X”是该复合名称的前缀。如果 X 为 null 或不是复合名称对象,则返回 false。
句法:
public boolean startsWith(Name n)
参数:此方法接受名称对象n ,它是要检查的可能为空的复合名称。
返回值:如果 n 是 CompositeName 并且是该复合名称的前缀,则此方法返回 true,否则返回 false。
下面的程序说明了 CompositeName.startsWith() 方法:
方案一:
// Java program to demonstrate
// CompositeName.startsWith()
import java.util.Properties;
import javax.naming.CompositeName;
import javax.naming.InvalidNameException;
public class GFG {
public static void main(String[] args)
throws InvalidNameException
{
// create composite name object
CompositeName CompositeName1
= new CompositeName("1:2:4:6");
CompositeName CompositeName2
= new CompositeName("2:4:6");
// apply startsWith()
boolean Flag
= CompositeName1
.startsWith(CompositeName2);
// print value
if (Flag)
System.out.println(
"CompositeName1 starts with "
+ " CompositeName2");
else
System.out.println(
"CompositeName1 not starts with "
+ " CompositeName2");
}
}
输出:
CompositeName1 not starts with CompositeName2
方案二:
// Java program to demonstrate
// CompositeName.startsWith() method
import java.util.Properties;
import javax.naming.CompositeName;
import javax.naming.InvalidNameException;
public class GFG {
public static void main(String[] args)
throws InvalidNameException
{
// create composite name object
CompositeName CompositeName1
= new CompositeName(
"ca/eaaa/daaa/vaaa/a/b/z/y/x/f");
CompositeName CompositeName2
= new CompositeName(
"ca/eaaa/daaa");
// apply startsWith()
boolean Flag
= CompositeName1
.startsWith(CompositeName2);
// print value
if (Flag)
System.out.println(
"CompositeName1 starts with "
+ " CompositeName2");
else
System.out.println(
"CompositeName1 not starts with "
+ " CompositeName2");
}
}
输出:
CompositeName1 starts with CompositeName2
参考资料:https://docs.oracle.com/javase/10/docs/api/javax/naming/CompositeName.html#startsWith(javax.naming.Name)