Python程序按子字符串范围对字符串进行排序

给定一个字符串列表，按子字符串的范围排序。

Input : test_list = [“geeksforgeeks”, “best”, “geeks”, “preparation”, “interview”], i, j = 1, 3 
Output : [‘geeksforgeeks’, ‘geeks’, ‘best’, ‘interview’, ‘preparation’]

Explanation : “eek” < “eek” < “est” < “nte” < “rep”.

Input : test_list = [“apple”, “orange”, “banana”], i, j = 2, 4 
Output : [‘orange’, ‘banana’, ‘apple’] 
Explanation : “ang” < “nan” < “ple”. 

方法 #1：使用 sort() + 切片

在这里，我们使用 sort() 执行排序任务，使用切片完成提取范围的任务。

Python3

# Python3 code to demonstrate working of 
# Sort Strings By Substring Range
# Using sort() + slicing
  
# helper function
def get_substr(test_str):
      
    # getting range
    return test_str[i : j]
  
# initializing list
test_list = ["geeksforgeeks", "best", "geeks", "preparation"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing range 
i, j = 1, 3
  
# calling func.
test_list.sort(key=get_substr)
  
# printing result 
print("Strings after sorting : " + str(test_list))

输出

The original list is : [‘geeksforgeeks’, ‘best’, ‘geeks’, ‘preparation’]
Strings after sorting : [‘geeksforgeeks’, ‘geeks’, ‘best’, ‘preparation’]

方法 #2：使用 lambda函数+ sort() + 切片

在这种情况下，我们使用 lambda函数而不是调用外部函数来执行切片。

蟒蛇3

# Python3 code to demonstrate working of 
# Sort Strings By Substring Range
# Using lambda function + sort() + slicing
  
# initializing list
test_list = ["geeksforgeeks", "best", "geeks", "preparation"]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initializing range 
i, j = 1, 3
  
# lambda function providing sort fnc.
test_list.sort(key=lambda test_str : test_str[i : j])
  
# printing result 
print("Strings after sorting : " + str(test_list))

输出

The original list is : [‘geeksforgeeks’, ‘best’, ‘geeks’, ‘preparation’]
Strings after sorting : [‘geeksforgeeks’, ‘geeks’, ‘best’, ‘preparation’]