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📜  Java中的 ByteBuffer getInt() 方法及示例

📅  最后修改于: 2022-05-13 01:55:52.306000             🧑  作者: Mango

Java中的 ByteBuffer getInt() 方法及示例

获取整数()

Java.nio.ByteBuffer类的getInt()方法用于读取该缓冲区当前位置接下来的四个字节,按照当前字节顺序将它们组合成一个int值,然后将该位置加四。

句法:

public abstract int getInt()

返回值:该方法返回缓冲区当前位置的 int 值

抛出:此方法抛出BufferUnderflowException – 如果此缓冲区中剩余的字节少于四个。
以下是说明 getInt() 方法的示例:

示例 1:

// Java program to demonstrate
// getInt() method
  
import java.nio.*;
import java.util.*;
  
public class GFG {
  
    public static void main(String[] args)
    {
  
        // Declaring the capacity of the ByteBuffer
        int capacity = 12;
  
        // Creating the ByteBuffer
        try {
  
            // creating object of ByteBuffer
            // and allocating size capacity
            ByteBuffer bb = ByteBuffer.allocate(capacity);
  
            // putting the int value in the bytebuffer
            bb.asIntBuffer()
                .put(10)
                .put(20)
                .put(30);
  
            // rewind the Bytebuffer
            bb.rewind();
  
            // print the ByteBuffer
            System.out.println("Original ByteBuffer: ");
            for (int i = 1; i <= capacity / 4; i++)
                System.out.print(bb.getInt() + " ");
  
            // rewind the Bytebuffer
            bb.rewind();
  
            // Reads the Int at this buffer's current position
            // using getInt() method
            int value = bb.getInt();
  
            // print the int value
            System.out.println("\n\nByte Value: " + value);
  
            // Reads the int at this buffer's next position
            // using getInt() method
            int value1 = bb.getInt();
  
            // print the int value
            System.out.println("Next Byte Value: " + value1);
        }
  
        catch (BufferUnderflowException e) {
  
            System.out.println("\nException Thrown : " + e);
        }
    }
}
输出:
Original ByteBuffer: 
10 20 30 

Byte Value: 10
Next Byte Value: 20

示例 2:

// Java program to demonstrate
// getInt() method
  
import java.nio.*;
import java.util.*;
  
public class GFG {
  
    public static void main(String[] args)
    {
  
        // Declaring the capacity of the ByteBuffer
        int capacity = 8;
  
        // Creating the ByteBuffer
        try {
  
            // creating object of ByteBuffer
            // and allocating size capacity
            ByteBuffer bb = ByteBuffer.allocate(capacity);
  
            // putting the int value in the bytebuffer
            bb.asIntBuffer()
                .put(10)
                .put(20);
  
            // rewind the Bytebuffer
            bb.rewind();
  
            // print the ByteBuffer
            System.out.println("Original ByteBuffer: ");
            for (int i = 1; i <= capacity / 4; i++)
                System.out.print(bb.getInt() + " ");
  
            // rewind the Bytebuffer
            bb.rewind();
  
            // Reads the Int at this buffer's current position
            // using getInt() method
            int value = bb.getInt();
  
            // print the int value
            System.out.println("\n\nByte Value: " + value);
  
            // Reads the int at this buffer's next position
            // using getInt() method
            int value1 = bb.getInt();
  
            // print the int value
            System.out.println("Next Byte Value: " + value1);
  
            // Reads the int at this buffer's next position
            // using getInt() method
            int value2 = bb.getInt();
        }
  
        catch (BufferUnderflowException e) {
            System.out.println("\nthere are fewer than "
                               + "four bytes remaining in this buffer");
            System.out.println("Exception Thrown : " + e);
        }
    }
}
输出:
Original ByteBuffer: 
10 20 

Byte Value: 10
Next Byte Value: 20

there are fewer than four bytes remaining in this buffer
Exception Thrown : java.nio.BufferUnderflowException

参考: https://docs.oracle.com/javase/9/docs/api/ Java/nio/ByteBuffer.html#getInt–

getInt(整数索引)

ByteBuffergetInt(int index)方法用于读取给定索引处的四个字节,根据当前字节顺序将它们组合成一个 int 值。

句法 :

public abstract int getInt(int index)

参数:此方法以索引(将从中读取字节的索引)作为参数。

返回值:此方法返回给定索引处的 int 值。

异常:此方法抛出IndexOutOfBoundsException 。如果 index 为负数或不小于缓冲区的限制,则会引发此异常。

以下是说明getInt(int index)方法的示例:

示例 1:

// Java program to demonstrate
// getInt() method
  
import java.nio.*;
import java.util.*;
  
public class GFG {
  
    public static void main(String[] args)
    {
  
        // Declaring the capacity of the ByteBuffer
        int capacity = 8;
  
        // Creating the ByteBuffer
        try {
  
            // creating object of ByteBuffer
            // and allocating size capacity
            ByteBuffer bb = ByteBuffer.allocate(capacity);
  
            // putting the int value in the bytebuffer
            bb.asIntBuffer()
                .put(10)
                .put(20);
  
            // rewind the Bytebuffer
            bb.rewind();
  
            // print the ByteBuffer
            System.out.println("Original ByteBuffer: ");
            for (int i = 1; i <= capacity / 4; i++)
                System.out.print(bb.getInt() + " ");
  
            // rewind the Bytebuffer
            bb.rewind();
  
            // Reads the Int at this buffer's current position
            // using getInt() method
            int value = bb.getInt(0);
  
            // print the int value
            System.out.println("\n\nByte Value: " + value);
  
            // Reads the int at this buffer's next position
            // using getInt() method
            int value1 = bb.getInt(4);
  
            // print the int value
            System.out.println("Next Byte Value: " + value1);
        }
  
        catch (IndexOutOfBoundsException e) {
  
            System.out.println("\nindex is negative or smaller "
                               + "than the buffer's limit, minus seven");
            System.out.println("Exception Thrown : " + e);
        }
    }
}
输出:
Original ByteBuffer: 
10 20 

Byte Value: 10
Next Byte Value: 20

示例 2:

// Java program to demonstrate
// getInt() method
  
import java.nio.*;
import java.util.*;
  
public class GFG {
  
    public static void main(String[] args)
    {
  
        // Declaring the capacity of the ByteBuffer
        int capacity = 8;
  
        // Creating the ByteBuffer
        try {
  
            // creating object of ByteBuffer
            // and allocating size capacity
            ByteBuffer bb = ByteBuffer.allocate(capacity);
  
            // putting the int value in the bytebuffer
            bb.asIntBuffer()
                .put(10)
                .put(20);
  
            // rewind the Bytebuffer
            bb.rewind();
  
            // print the ByteBuffer
            System.out.println("Original ByteBuffer: ");
            for (int i = 1; i <= capacity / 4; i++)
                System.out.print(bb.getInt() + " ");
  
            // rewind the Bytebuffer
            bb.rewind();
  
            // Reads the Int at this buffer's current position
            // using getInt() method
            int value = bb.getInt(0);
  
            // print the int value
            System.out.println("\n\nByte Value: " + value);
  
            // Reads the int at this buffer's next position
            // using getInt() method
            int value1 = bb.getInt(7);
  
            // print the int value
            System.out.println("Next Byte Value: " + value1);
        }
  
        catch (IndexOutOfBoundsException e) {
  
            System.out.println("\nindex is negative or smaller"
                               + " than the buffer's limit, minus seven");
            System.out.println("Exception Thrown : " + e);
        }
    }
}
输出:
Original ByteBuffer: 
10 20 

Byte Value: 10

index is negative or smaller than the buffer's limit, minus seven
Exception Thrown : java.lang.IndexOutOfBoundsException

参考: https://docs.oracle.com/javase/9/docs/api/ Java/nio/ByteBuffer.html#getInt-int-