Python| os.path.sameopenfile() 方法

Python中的OS 模块提供了与操作系统交互的功能。操作系统属于 Python 的标准实用程序模块。该模块提供了一种使用操作系统相关功能的可移植方式。 os.path模块是Python中OS 模块的子模块，用于常见的路径名操作。
Python中的os.path.sameopenfile()方法用于检查给定的文件描述符是否引用同一个文件。
文件描述符是与当前进程已打开的文件相对应的小整数值。
文件描述符指示资源并充当句柄以执行各种较低级别的 I/O 操作，如读取、写入、发送等。
例如：标准输入通常是值为 0 的文件描述符，标准输出通常是值为 1 的文件描述符，标准错误通常是值为 2 的文件描述符。当前进程打开的进一步文件将获得值 3、4、5 和很快。

Syntax: os.path.sameopenfile(fd1, fd2)
Parameter:
fd1: A file descriptor.
fd2: A file descriptor.
Return Type: This method returns a Boolean value of class bool. This method returns True if both file descriptor fd1 and fd2 refer to the same file otherwise returns false.

编程需要懂一点英语

代码：使用 os.path.sameopenfile() 方法检查给定的文件描述符是否引用同一个文件。

Python3

# Python program to explain os.path.sameopenfile() method
   
# importing os module
import os
 
# Path
path = "/home / ihritik / Desktop / file1.txt"
 
 
# open the file represented by
# the above given path and get
# the file descriptor associated
# with it using os.open() method
fd1 = os.open(path, os.O_RDONLY)
 
 
# open the file represented by
# the above given path and get
# the file object corresponding
# to the opened file
# using open() method
File = open(path, mode ='r')
 
 
# Get the file descriptor
# associated with the
# file object 'File'
fd2 = File.fileno()
 
 
# check whether the file descriptor
# fd1 and fd2 refer to same
# file or not
sameFile = os.path.sameopenfile(fd1, fd2)
 
# Print the result
print(sameFile)
 
 
# Path
path2 = "/home / ihritik / Documents / sample.txt"
 
 
# open the file represented by
# the above given path and get
# the file descriptor associated
# with it using os.open() method
fd3 = os.open(path2, os.O_RDONLY)
 
 
# check whether the file descriptor
# fd1 and fd3 refer to same
# file or not
sameFile = os.path.sameopenfile(fd1, fd3)
 
# Print the result
print(sameFile)
 
 
# close file descriptors
close(fd1)
close(fd2)
close(fd3)

输出：

True
False

参考： https://docs。 Python.org/3/library/os.path.html