Python – 检查元组中是否存在任何列表元素

给定一个元组，检查其中是否存在任何列表元素。

Input : test_tup = (4, 5, 10, 9, 3), check_list = [6, 7, 10, 11] 
Output : True 
Explanation : 10 occurs in both tuple and list.

Input : test_tup = (4, 5, 12, 9, 3), check_list = [6, 7, 10, 11] 
Output : False 
Explanation : No common elements. 
 

方法#1：使用循环

在此，我们保留一个布尔变量，记录所有元素，如果找到，则返回 True，否则返回 False。

Python3

# Python3 code to demonstrate working of
# Check if any list element is present in Tuple
# Using loop
 
# initializing tuple
test_tup = (4, 5, 7, 9, 3)
 
# printing original tuple
print("The original tuple is : " + str(test_tup))
 
# initializing list
check_list = [6, 7, 10, 11]
 
res = False
for ele in check_list:
     
    # checking using in operator
    if ele in test_tup :
        res = True
        break
 
# printing result
print("Is any list element present in tuple ? : " + str(res))

输出

The original tuple is : (4, 5, 7, 9, 3)
Is any list element present in tuple ? : True

方法 #2：使用 any()

这将返回 True，如果在元组中找到列表的任何元素，则使用 in 运算符进行测试。

Python3

# Python3 code to demonstrate working of
# Check if any list element is present in Tuple
# Using any()
 
# initializing tuple
test_tup = (4, 5, 7, 9, 3)
 
# printing original tuple
print("The original tuple is : " + str(test_tup))
 
# initializing list
check_list = [6, 7, 10, 11]
 
# generator expression is used for iteration
res = any(ele in test_tup for ele in check_list)
 
# printing result
print("Is any list element present in tuple ? : " + str(res))

输出

The original tuple is : (4, 5, 7, 9, 3)
Is any list element present in tuple ? : True