拆分数组并将第一部分添加到末尾 |设置 2
给定一个数组并将其从指定位置拆分,并将数组的第一部分添加到末尾。
例子:
Input : arr[] = {12, 10, 5, 6, 52, 36}
k = 2
Output : arr[] = {5, 6, 52, 36, 12, 10}
Explanation : Split from index 2 and first
part {12, 10} add to the end .
Input : arr[] = {3, 1, 2}
k = 1
Output : arr[] = {1, 2, 3}
Explanation : Split from index 1 and first
part add to the end.
此处讨论 AO(n*k) 解。
这个问题可以使用下面讨论的反转算法在 O(n) 时间内解决,
1. 将数组从 0 反转为 n – 1(其中 n 是数组的大小)。
2. 将数组从 0 反转为 n – k – 1。
3. 将数组从 n-k 反转为 n-1。
C++
// C++ program to Split the array and
// add the first part to the end
#include
using namespace std;
/* Function to reverse arr[] from index start to end*/
void rvereseArray(int arr[], int start, int end)
{
while (start < end) {
int temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
}
// Function to print an array
void printArray(int arr[], int size)
{
for (int i = 0; i < size; i++)
cout << arr[i] << " ";
}
/* Function to left rotate arr[] of size n by k */
void splitArr(int arr[], int k, int n)
{
rvereseArray(arr, 0, n - 1);
rvereseArray(arr, 0, n - k - 1);
rvereseArray(arr, n - k, n - 1);
}
/* Driver program to test above functions */
int main()
{
int arr[] = { 12, 10, 5, 6, 52, 36 };
int n = sizeof(arr) / sizeof(arr[0]);
int k = 2;
// Function calling
splitArr(arr, k, n);
printArray(arr, n);
return 0;
}
Java
// Java program to Split the array and
// add the first part to the end
class Geeks
{
/* Function to reverse arr[] from index start to end*/
static void rvereseArray(int arr[], int start, int end)
{
while (start < end) {
int temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
}
// Function to print an array
static void printArray(int arr[], int size)
{
for (int i = 0; i < size; i++)
System.out.print(arr[i] +" ");
}
/* Function to left rotate arr[] of size n by k */
static void splitArr(int arr[], int k, int n)
{
rvereseArray(arr, 0, n - 1);
rvereseArray(arr, 0, n - k - 1);
rvereseArray(arr, n - k, n - 1);
}
/* Driver program to test above functions */
public static void main(String args[])
{
int arr[] = { 12, 10, 5, 6, 52, 36 };
int n = arr.length;
int k = 2;
// Function calling
splitArr(arr, k, n);
printArray(arr, n);
}
}
// This code is contributed by ankita_saini.
Python3
# Python3 program to Split the array
# and add the first part to the end
# Function to reverse arr[]
# from index start to end*/
def rvereseArray(arr, start, end):
while start < end :
temp = arr[start]
arr[start] = arr[end]
arr[end] =temp
start += 1
end -= 1
# Function to print an array
def printArray(arr, n) :
for i in range(n):
print(arr[i], end = " ")
# Function to left rotate
# arr[] of size n by k */
def splitArr(arr, k, n):
rvereseArray(arr, 0, n - 1)
rvereseArray(arr, 0, n - k - 1)
rvereseArray(arr, n - k, n - 1)
# Driver Code
arr = [12, 10, 5, 6, 52, 36]
n = len(arr)
k = 2
splitArr(arr, k, n)
printArray(arr, n)
# This code is contributed
# by Shrikant13
C#
// C# program to Split the array and
// add the first part to the end
using System;
class GFG
{
/* Function to reverse arr[] from index start to end*/
static void rvereseArray(int[] arr, int start, int end)
{
while (start < end)
{
int temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
}
// Function to print an array
static void printArray(int[] arr, int size)
{
for (int i = 0; i < size; i++)
Console.Write(arr[i] +" ");
}
/* Function to left rotate arr[] of size n by k */
static void splitArr(int[] arr, int k, int n)
{
rvereseArray(arr, 0, n - 1);
rvereseArray(arr, 0, n - k - 1);
rvereseArray(arr, n - k, n - 1);
}
// Driver code
public static void Main()
{
int[] arr = { 12, 10, 5, 6, 52, 36 };
int n = arr.Length;
int k = 2;
// Function calling
splitArr(arr, k, n);
printArray(arr, n);
}
}
// This code is contributed
// by Akanksha Rai(Abby_akku)
PHP
Javascript
输出:
5 6 52 36 12 10