Python|三重列表差异

之前已经处理了两个列表之间的差异，但有时，我们可以有两个以上的列表，我们需要找到一个列表与其他列表的相互差异。这类问题在许多领域都有应用。让我们讨论一些可以解决这个问题的方法。

方法 #1：使用map() + set() + 列表推导

上述 3 个功能的组合可用于执行此特定任务。 map函数可用于将列表转换为 set函数的集合，列表推导可用于获取每个列表的新互差列表。

# Python3 code to demonstrate
# triple list difference 
# using map() + set() + list comprehension
  
# initializing lists 
test_list1 = [1, 5, 6, 4, 7]
test_list2 = [8, 4, 3]
test_list3 = [9, 10, 3, 5]
  
# printing original lists
print("The original list 1 : " + str(test_list1))
print("The original list 2 : " + str(test_list2))
print("The original list 3 : " + str(test_list3))
  
# using map() + set() + list comprehension
# triple list difference 
temp1, temp2, temp3 = map(set, (test_list1, test_list2, test_list3))
res1 = [ele for ele in test_list1 if ele not in temp2 and ele not in temp3]
res2 = [ele for ele in test_list2 if ele not in temp1 and ele not in temp3]
res3 = [ele for ele in test_list3 if ele not in temp2 and ele not in temp1]
  
# print result
print("The mutual difference list are : "
      + str(res1) + " " + str(res2) + " " + str(res3))

输出 ：

The original list 1 : [1, 5, 6, 4, 7]
The original list 2 : [8, 4, 3]
The original list 3 : [9, 10, 3, 5]
The mutual difference list are : [1, 6, 7] [8] [9, 10]

方法 #2：使用map() + set() + "-"运算符

如果不想使用列表推导，这个问题也可以通过减号运算符来解决。减号运算符可以执行布尔匹配差异来计算有效集差异。

# Python3 code to demonstrate
# triple list difference 
# using map() + set() + "-" operator
  
# initializing lists 
test_list1 = [1, 5, 6, 4, 7]
test_list2 = [8, 4, 3]
test_list3 = [9, 10, 3, 5]
  
# printing original lists
print("The original list 1 : " + str(test_list1))
print("The original list 2 : " + str(test_list2))
print("The original list 3 : " + str(test_list3))
  
# using map() + set() + "-" operator
# triple list difference 
temp1, temp2, temp3 = map(set, (test_list1, test_list2, test_list3))
res1 = temp1 - temp2 - temp3
res2 = temp2 - temp3 - temp1
res3 = temp3 - temp1 - temp2
res1, res2, res3 = map(list, (res1, res2, res3))
  
# print result
print("The mutual difference list are : "
      + str(res1) + " " + str(res2) + " " + str(res3))

输出 ：

The original list 1 : [1, 5, 6, 4, 7]
The original list 2 : [8, 4, 3]
The original list 3 : [9, 10, 3, 5]
The mutual difference list are : [1, 6, 7] [8] [9, 10]