Python - 列表中的相邻元素

给定一个列表，为每个元素提取下一个和上一个元素。

Input : test_list = [3, 7, 9, 3] 
Output : [(None, 7), (3, 9), (7, 3), (9, None)] 
Explanation : for 7 left element is 3 and right, 9.

Input : test_list = [3, 7, 3] 
Output : [(None, 7), (3, 3), (7, None)] 
Explanation : for 7 left element is 3 and right, 3. 

方法：使用循环

在这里，我们迭代每个元素并使用元素访问获取下一个和上一个元素。

Python3

# Python3 code to demonstrate working of
# Adjacent elements in List
# Using loop
  
  
# Function to find adjacent
# elements in List
def findAdjacentElements(test_list):
    res = []
    for idx, ele in enumerate(test_list):
  
        # Checking for all cases to append
        if idx == 0:
            res.append((None, test_list[idx + 1]))
        elif idx == len(test_list) - 1:
            res.append((test_list[idx - 1], None))
        else:
            res.append((test_list[idx - 1], test_list[idx + 1]))
    return res
  
  
# Initializing list
input_list = [3, 7, 8, 2, 1, 5, 8, 9, 3]
  
# Printing original list
print("The original list is:", input_list)
  
  
# printing result
print("The Adjacent elements list:", findAdjacentElements(input_list))

输出：

The original list is: [3, 7, 8, 2, 1, 5, 8, 9, 3]
The Adjacent elements list: [(None, 7), (3, 8), (7, 2), (8, 1), (2, 5), (1, 8), (5, 9), (8, 3), (9, None)]