📅  最后修改于: 2022-03-11 15:05:23.734000             🧑  作者: Mango
SELECT id, i.title AS item_title, t.tag_array
FROM items i
JOIN ( -- or LEFT JOIN ?
SELECT it.item_id AS id, array_agg(t.title) AS tag_array
FROM items_tags it
JOIN tags t ON t.id = it.tag_id
GROUP BY it.item_id
) t USING (id);