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📜  mysql 选择名称类似的表 - SQL 代码示例

📅  最后修改于: 2022-03-11 15:05:20.849000             🧑  作者: Mango

代码示例2
select table_schema as database_name,
    table_name
from information_schema.tables
where table_type = 'BASE TABLE'
    and table_name like 'cu%'
order by table_schema,
     table_name;