Python – 过滤具有所有相同元素的元组

给定元组列表，过滤具有相同值的元组。

Input : test_list = [(5, 6, 5, 5), (6, 6, 6), (9, 10)] 
Output : [(6, 6, 6)] 
Explanation : 1 tuple with same elements.

Input : test_list = [(5, 6, 5, 5), (6, 5, 6), (9, 10)] 
Output : [] 
Explanation : No tuple with same elements.
 

方法 #1：使用列表理解 + set() + len()

在此，我们检查集合转换元组的长度是否为 1，如果检查出，则将元组添加到结果中，否则省略。

Python3

# Python3 code to demonstrate working of
# Filter similar elements Tuples
# Using list comprehension + set() + len()
 
# initializing list
test_list = [(5, 6, 5, 5), (6, 6, 6), (1, 1), (9, 10)]
 
# printing original list
print("The original list is : " + str(test_list))
 
# length is computed using len()
res = [sub for sub in test_list if len(set(sub)) == 1]
         
# printing results
print("Filtered Tuples : " + str(res))

输出

The original list is : [(5, 6, 5, 5), (6, 6, 6), (1, 1), (9, 10)]
Filtered Tuples : [(6, 6, 6), (1, 1)]

方法 #2：使用 filter() + lambda + set() + len()

在此，我们使用 filter() 执行过滤任务，并使用 set() 和 len() 在 lambda函数中检查单个元素逻辑。

Python3

# Python3 code to demonstrate working of
# Filter similar elements Tuples
# Using filter() + lambda + set() + len()
 
# initializing list
test_list = [(5, 6, 5, 5), (6, 6, 6), (1, 1), (9, 10)]
 
# printing original list
print("The original list is : " + str(test_list))
 
# end result converted to list object
# filter extracts req. tuples
res = list(filter(lambda sub : len(set(sub)) == 1, test_list))
         
# printing results
print("Filtered Tuples : " + str(res))

输出

The original list is : [(5, 6, 5, 5), (6, 6, 6), (1, 1), (9, 10)]
Filtered Tuples : [(6, 6, 6), (1, 1)]