📅  最后修改于: 2023-12-03 15:00:47.974000             🧑  作者: Mango
In Flutter, we can use a ShowDialog
widget to display a popup dialog on the screen. We can set the barrierDismissible
property of the ShowDialog
widget to control whether or not the user can dismiss the dialog by tapping outside of it.
showDialog(
context: context,
barrierDismissible: true/false,
// other dialog properties
);
context
: The build context for the current widget tree.barrierDismissible
: A Boolean value that determines whether or not the dialog can be dismissed by tapping outside of it.To display a dialog with a dismissible barrier, we can set the barrierDismissible
property of the ShowDialog
widget to true
. In this case, the user can dismiss the dialog by tapping outside of it.
showDialog(
context: context,
barrierDismissible: true,
builder: (BuildContext context) {
return AlertDialog(
title: Text('Dismissable Dialog'),
content: Text('Tap anywhere outside the dialog to dismiss.'),
// other dialog properties
);
},
);
To display a dialog with a non-dismissible barrier, we can set the barrierDismissible
property of the ShowDialog
widget to false
. In this case, the user cannot dismiss the dialog by tapping outside of it.
showDialog(
context: context,
barrierDismissible: false,
builder: (BuildContext context) {
return AlertDialog(
title: Text('Non-Dismissable Dialog'),
content: Text('This dialog cannot be dismissed by tapping outside.'),
// other dialog properties
);
},
);
In conclusion, the barrierDismissible
property of the ShowDialog
widget allows us to control whether or not the user can dismiss a dialog by tapping outside of it. This feature can be useful in situations where we want to ensure that the user interacts with the dialog before continuing.