Python - 按值列表中的最大/最小元素对字典进行排序

给定字典，根据字典值列表中存在的最大或最小元素执行排序。

Input : test_dict = {“Gfg” : [6, 4], “best” : [8, 4], “for” : [7, 13], “geeks” : [15, 5]}
Output : {‘geeks’: [15, 5], ‘for’: [7, 13], ‘best’: [8, 4], ‘Gfg’: [6, 4]}
Explanation : Max of values is 15, occurs in “geeks” key, hence at 1st position and so on.

Input : test_dict = {“Gfg” : [6, 4], “best” : [8, 4]}
Output : {‘best’: [8, 4], ‘Gfg’: [6, 4]}
Explanation : Max of values is 8, occurs in “best” key, hence at 1st position and so on.

方法 #1：使用 sorted() + max() + 字典理解 + reverse + lambda

以上功能的组合可以解决这个问题。在此，我们使用 sorted() 执行排序任务，使用 max() 提取最大值，使用 reverse 获取最大元素第 1 个，并且使用 lambda函数将 max() 逻辑扩展到 sorted 函数。

Python3

# Python3 code to demonstrate working of 
# Sort dictionary by max / min element in value list
# Using sorted() + max() + dictionary comprehension + reverse + lambda
  
# initializing dictionary
test_dict = {"Gfg" : [6, 4], "is" : [10, 3], "best" : [8, 4],
             "for" : [7, 13], "geeks" : [15, 5]}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# lambda function driving maximum operation on sorted()
# dictionary comprehension used to reconstruct dictionary
res = {key: test_dict[key] for key in sorted(test_dict, key = lambda ele: max(test_dict[ele]),
       reverse = True)}
  
# printing result 
print("Reverse Sorted dictionary on basis of max values : " + str(res))

输出

The original dictionary is : {'Gfg': [6, 4], 'is': [10, 3], 'best': [8, 4], 'for': [7, 13], 'geeks': [15, 5]}
Reverse Sorted dictionary on basis of max values : {'geeks': [15, 5], 'for': [7, 13], 'is': [10, 3], 'best': [8, 4], 'Gfg': [6, 4]}

方法 #2：使用 sorted() + min() + 字典理解 + reverse + lambda

这与上述函数的方法类似，唯一的区别是我们根据字典值中的最高最小值进行排序。

蟒蛇3

# Python3 code to demonstrate working of 
# Sort dictionary by max / min element in value list
# Using sorted() + min() + dictionary comprehension + reverse + lambda
  
# initializing dictionary
test_dict = {"Gfg" : [6, 4], "is" : [10, 3], "best" : [8, 4],
             "for" : [7, 13], "geeks" : [15, 5]}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# lambda function driving minimum operation on sorted()
# dictionary comprehension used to reconstruct dictionary
res = {key: test_dict[key] for key in sorted(test_dict, key = lambda ele: min(test_dict[ele]),
       reverse = True)}
  
# printing result 
print("Reverse Sorted dictionary on basis of min values : " + str(res)) 

输出

The original dictionary is : {'Gfg': [6, 4], 'is': [10, 3], 'best': [8, 4], 'for': [7, 13], 'geeks': [15, 5]}
Reverse Sorted dictionary on basis of min values : {'for': [7, 13], 'geeks': [15, 5], 'Gfg': [6, 4], 'best': [8, 4], 'is': [10, 3]}