从阵列中删除所有奇数频率元素

给定一个包含大小为N的整数的数组arr ，任务是从数组中删除所有具有奇数频率的元素。

例子：

Input: arr[] = {3, 3, 3, 2, 2, 4, 7, 7}
Output: {2, 2, 7, 7}
Explanation:
Frequency of 3 = 3
Frequency of 2 = 2
Frequency of 4 = 1
Frequency of 7 = 2
Therefore, the elements 3 and 4 have odd frequencies, and hence the are removed.

Input: arr[] = {1, 3, 3, 1, 2, 5, 6, 5}
Output: {1, 3, 3, 1, 5, 5}

方法：

• 创建一个映射，并将数组中每个元素的频率存储到同一映射。
• 然后，遍历数组，并借助地图找出哪些元素具有奇数频率。
• 忽略所有那些具有奇数频率的元素，并打印其余部分

下面是上述方法的实现：

C++

// C++ program to removes all odd
// frequency elements from an Array
  
#include 
using namespace std;
  
// Function that removes the
// elements which have odd
// frequencies in the array
void remove(int arr[], int n)
{
    // Create a map to store the
    // frequency of each element
    unordered_map m;
    for (int i = 0; i < n; i++) {
        m[arr[i]]++;
    }
  
    // Remove the elements which
    // have odd frequencies
    for (int i = 0; i < n; i++) {
  
        // If the element has
        // odd frequency then skip
        if ((m[arr[i]] & 1))
            continue;
  
        cout << arr[i] << ", ";
    }
}
  
// Driver code
int main()
{
    int arr[]
        = { 3, 3, 3, 2,
            2, 4, 7, 7 };
    int n = sizeof(arr) / sizeof(arr[0]);
  
    // Function call
    remove(arr, n);
  
    return 0;
}

Java

// Java program to removes all odd
// frequency elements from an Array
import java.util.*;
  
class GFG {
  
    // Function that removes the
    // elements which have odd
    // frequencies in the array
    static void remove(int arr[], int n) {
        // Create a map to store the
        // frequency of each element
        HashMap mp = new HashMap();
        for (int i = 0; i < n; i++) {
            if (mp.containsKey(arr[i])) {
                mp.put(arr[i], mp.get(arr[i]) + 1);
            } else {
                mp.put(arr[i], 1);
            }
        }
  
        // Remove the elements which
        // have odd frequencies
        for (int i = 0; i < n; i++) {
  
            // If the element has
            // odd frequency then skip
            if ((mp.containsKey(arr[i]) && mp.get(arr[i]) % 2 == 1))
                continue;
  
            System.out.print(arr[i] + ", ");
        }
    }
  
    // Driver code
    public static void main(String[] args) {
        int arr[] = { 3, 3, 3, 2, 2, 4, 7, 7 };
        int n = arr.length;
  
        // Function call
        remove(arr, n);
  
    }
}
  
// This code is contributed by Rajput-Ji

Python3

# Python3 program to removes all odd 
# frequency elements from an Array 
  
# Function that removes the 
# elements which have odd 
# frequencies in the array 
def remove(arr,  n) :
  
    # Create a map to store the
    # frequency of each element
    m = dict.fromkeys(arr,0);
    for i in range(n) :
        m[arr[i]] += 1;
          
    # Remove the elements which
    # have odd frequencies
    for i in range(n) :
  
        # If the element has 
        # odd frequency then skip
        if ((m[arr[i]] & 1)) :
            continue;
              
        print(arr[i],end= ", "); 
  
# Driver code 
if __name__ == "__main__" :
  
    arr    = [ 3, 3, 3, 2, 
            2, 4, 7, 7 ]; 
    n = len(arr); 
  
    # Function call 
    remove(arr, n); 
  
# This code is contributed by Yash_R

C#

// C# program to removes all odd
// frequency elements from an Array
using System;
using System.Collections.Generic;
  
class GFG {
   
    // Function that removes the
    // elements which have odd
    // frequencies in the array
    static void remove(int []arr, int n) {
  
        // Create a map to store the
        // frequency of each element
        Dictionary mp = new Dictionary();
        for (int i = 0; i < n; i++) {
            if (mp.ContainsKey(arr[i])) {
                mp[arr[i]] =  mp[arr[i]] + 1;
            } else {
                mp.Add(arr[i], 1);
            }
        }
   
        // Remove the elements which
        // have odd frequencies
        for (int i = 0; i < n; i++) {
   
            // If the element has
            // odd frequency then skip
            if ((mp.ContainsKey(arr[i]) && mp[arr[i]] % 2 == 1))
                continue;
   
            Console.Write(arr[i] + ", ");
        }
    }
   
    // Driver code
    public static void Main(String[] args) {
        int []arr = { 3, 3, 3, 2, 2, 4, 7, 7 };
        int n = arr.Length;
   
        // Function call
        remove(arr, n);
    }
}
  
// This code is contributed by 29AjayKumar

输出：

2, 2, 7, 7,