这是用于放置准备的WIPRO模型放置纸。这份安置文件将涵盖WIPRO招聘活动中提出的才能,逻辑和推理,口头和编码问题,并且还将严格遵循WIPRO采访中提出的问题模式。建议解决以下每个问题,以增加通过WIPRO采访的机会。
定量分析
- 两个数字的乘积为108,其平方和为225。数字的差为:
。- 5
- 4
- 3
- 都不是
回答:
57
解释:
Let the numbers be x and y.
Then xy = 108 and x2 + y2 = 225
(x –y)2 = x2 + y2 – 2xy
(x –y)2 = 225 – 216
(x –y)2 = 9
Therefore (x –y) = 3 - 以下哪一个除数最多?
- 99
- 101
- 176
- 182
回答:
176
解释:
99 = 1 * 3 * 3 * 11
101 = 1 * 101
176 = 1 * 2 * 2 * 2 * 2 * 11
182 = 1 * 2 * 7 * 13
Clearly, 176 has the most number of divisors. - 两个数字的比率为3:2。如果数字的LCM是60,那么较小的数字是?
- 20
- 30
- 40
- 50
回答:
20
解释:
say, 1st number =3x
2nd number =2x
LCM of numbers = 6x
given LCM = 60
=> x6 = 60
=>x = 10 - 雇用了6名男性和10名女性,修建了360公里长的道路。通过每天工作6个小时,他们能够在15天之内完成150公里的路程。 15天后,又雇用了两名男子,并撤走了四名妇女。而且,工作时间增加到一天7小时。如果2位男性和3位女性的每日工作能力相等,请找到完成工作所需的总天数。
- 19
- 35
- 34
- 50
回答:
34
解释:
We are given that the daily working power of 2 men and 3 women are equal.
=> 2 Em = 3 Ew
=> Em / Ew = 3/2, where ‘Em’ is the efficiency of 1 man and ‘Ew’ is the efficiency of 1 woman.
Therefore, the ratio of efficiency of man and woman = 3 : 2.
If ‘k’ is the constant of proportionality, Em = 3k and Ew = 2k.
Here, we need to apply the formula
=> (Mi Ei) D1 H1 / W1 = (Mj Ej) D2 H2 / W2, where
=> (Mi Ei) = (6 x 3k) + (10 x 2k)
=> (Mj Ej) = (8 x 3k) + (6 x 2k)
D1 = 15 days
D2 = Number of days after increasing men and reducing women
H1 = 6 hours
H2 = 7 hours
W1 = 150 km
W2 = 210 kmSo, we have
38k x 15 x 6 / 150 = 36k x D2 x 7 / 210
=> 38k x 6 = 12k x D2
=> D2 = 19 days
Therefore, total days required to complete the work = 15 + 19 = 34 days - 两根管子A和B分别可以在10小时和30小时内填充一个水箱。由于储罐中的泄漏,加满储罐需要花费2.5个小时以上。仅此泄漏就需要多少时间才能清空水箱?
- 20小时
- 25小时
- 30小时
- 35小时
回答:
30 hours
解释:
Let the capacity of the tank be LCM (10, 30) = 30 units
=> Efficiency of pipe A = 30 / 10 = 3 units / hour
=> Efficiency of pipe B = 30 / 30 = 1 units / hour
=> Combined efficiency of both pipes = 4 units / hour
Now, total time taken by A and B working together to fill the tank if there was no leak = 30 / 4 = 7.5 hours
=> Actual time taken = 7.5 + 2.5 = 10 hoursThe tank filled by A and B in these 2.5 hours is the extra work done to compensate the wastage by the leak in 10 hours.
=> 2.5 hours work of A and B together = 10 hours work of the leak
=> 2.5 x 4 = 10 x E, where ‘E’ is the efficiency of the leak.
=> E = 1 unit / hourTherefore, time taken by the leak alone to empty the full tank = 30 / 1 = 30 hours
- Max以9 km / h的平均速度完成旅程。他以6 km / h的速度覆盖了最初的9 km,花了1·5个小时来覆盖剩余的距离。找出他覆盖剩余距离的速度。
- 11公里/小时
- 12公里/小时
- 13公里/小时
- 14公里/小时
回答:
12 km/h
解释:
Let the required speed be x km/h.
Total time taken to finish his journey = (9/6 + 1·5) = 3 hours.
Total distance = 9 + 1·5x km.
Given, average speed = 9 km/h.
Therefore, (9 + 1·5x)/3 = 9
=> 9 + 1·5x = 27
=> 1·5x = 18
=> x = 12 km/h. - 火车在10秒内越过了一根电线杆。如果火车的长度是100米,那么以Kmph表示的火车速度是多少?
- 34
- 36
- 30
- 32
回答:
36
解释:
V = 100/10 = 10 m/s = 10*3600/1000 = 36Km/hr
- 杰克和罗伯特参加了考试。罗伯特比杰克少9分。杰克的分数是他们分数总和的56%。计算他们的个人分数。
- 22和33
- 41和35
- 40和35
- 42和33
回答:
42 and 33
解释:
Let Robert’s score be x. Then, Jack’s score = x+9.
Now, x+9 = 56% of [(x+9) + x]
=> x+9 = 14/25 × (2x + 9)
=> 25 × (x+9) = 14 × (2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99 => x = 33.
Therefore, Robert scored 33 marks and Jack scored 42 marks. - 在图书馆中,计算机,物理和数学书籍的比例为5:7:8。如果将图书收藏量分别增加40%,50%和75%,请找出新的比例:
- 3:9:5
- 7:5:3
- 2:3:4
- 2:5:4
回答:
2:3:4
解释:
40% increase will lead to a factor of 140 and similiarly 150 and 175
so the new ratio is
(5*140):(7*150):(8*175)
on solving we get 2:3:4
- 一个人的年龄是他母亲年龄的三分之一。 12岁之后,他的年龄将是母亲年龄的一半。他妈妈现在几岁?
- 30
- 34
- 38
- 36
回答:
36
解释:
Let the present ages of son and his mother are x years and 3x years.
Then (3x + 12) = 2( x + 12)
=> 3x + 12 = 2x + 24
=> x = 12
=> Present age of mother = 3x = 36 years
语文推理
- 改写书面或口语的字词是______________
- 释义
- 悖论
- 范例
- 石蜡
回答:
paraphrase
解释:
Paraphrase – To express something in different words so that it becomes easy for the listener to understand.
Paradox – A statement which sounds logical, but proves to be illogical when investigated.
Paradigm – A way of looking or thinking (perception) about something.
Paraffin – A flammable substance used in candles, polishes, etc.
So, A is the correct choice.
- 阿基米德说:“给我足够长的杠杆和支撑它的支点,我将带动世界。”上面的句子是___________语句的示例。
- 比喻的
- 抵押品
- 字面量
- 塑像
回答:
figurative
解释:
Here, we are talking about the figure of speech So, figurative is a figure of speech meaning:
Use of metamorphic meaning of words to explain your thoughts instead of literal use of them. - 现在担任市政专员的那个人是______________
- 大学的保安员
- 大学的一名保安
- 大学的保安员
- 大学的保安员
回答:
a security guard at the university
解释:
University considered as an organization that’s why article the used before university.
And Post of security is a general post, so article a has been used for security guard.So, option (B) is true.
- 在以下单词组中找到奇数。
mock, deride, praise, jeer
- 嘲笑
- 嘲笑
- 称赞
- 嘲笑
回答:
praise
解释:
Meanings
mock : tease
deride : poke/laugh at
praise : gratitude
jerk : foolSo except praise, all others are describing negative things.
-
In the present-day world, no individual or organization even think to plough a lonely furrow.
上面带下划线的短语的最佳含义是:
- 偷偷工作
- 保持一致
- 在没有他人帮助的情况下做
- 保持不结盟
回答:
do without the help of others
解释:
Meaning of the phrase-: Follow a course of action in which one is isolated or in which one can act independently.
- 我以前没有做过机械师,________我从小就一直在修汽车。
- 总是
- 然而
- 不再
- 已经
回答:
yet
解释:
Always is an adverb of frequency, like never, often, frequently, and usually.
Yet is a conjunction meaning nevertheless or however. Yet usually carries a sense of negation, so and yet means the same thing as but still.
No longer means not now as formerly; not any more.
We use already to show that something has happened sooner than it was expected to happen.Therefore, “yet” is the most appropriate choice here.
Option (B) is correct. - ____________通常用于过去完成的事情,并且仍然适用(多个事件)。
- 有/曾经/曾经
- 是/被
- 曾经/曾经/曾经
- 上述所有的
回答:
Had/has/have been
解释:
Had/has/have been is usually used for something that was done in the past and still applies (multiple events).
Was/were usually applies to something done in the past that no longer applies (single event).
So, option (A) is correct.
- 为以下项选择正确的SYNONYM:
坚硬的- 稳定的
- 虚弱的
- 颤抖的
- 松弛
回答:
A
- 为以下项选择正确的SYNONYM:
瘦- 大的
- 慷慨的
- 脆弱的
- 丰满
回答:
C
- 为以下项选择正确的ANTONYM:
高效的- 有能力的
- 有力
- 有能力的
- 不足
回答:
D
逻辑推理
- 在序列中找到错误的数字:
1,-6,18,-54,162,-486- 1个
- -6
- 162
- -486
回答:
1
解释:
2 * (-3) = -6
-6 * (-3) = 18
18 * (-3) = -54
-54 * (-3) = 162
162 * (-3) = -486 - 在序列中找到错误的数字:
2,8,12,20,30,42,56,72- 8
- 20
- 42
- 72
回答:
8
解释:
2 + 4 = 6,
6 + 6 = 12,
12 + 8 = 20,
20 + 10 = 30,
30 + 12 = 42,
42 + 14 = 56,
56 + 16 = 72解决问题3和4的方向:下面给出的每个问题均由一个陈述和/或一个问题以及下面给出的编号为I和II的两个陈述组成。您必须确定语句中提供的数据是否足以回答给定的问题。
阅读这两个陈述并给出答案
(a)如果仅陈述I的数据不足以回答问题,而仅陈述II的数据不足以回答问题。
(b)如果仅陈述II的数据足以回答问题,而仅陈述I的数据不足以回答问题。
(c)仅陈述I和陈述II中的数据是否足以回答该问题。
(d)陈述一和陈述二的数据是否不足以回答问题。
(e)是否必须同时使用表I和表II中的数据来回答这个问题。 - 每月的第14天?
这个月的一第二最后一天是星期二
二。该月的第三个星期六是第十七个- (一种)
- (b)
- (C)
- (d)
- (e)
回答:
(b) if the data in Statement II alone is sufficient to answer the question, while the data in Statement I alone is not sufficient to answer the question.
- A与B有什么关系?
陈述一。乙只有一个兄弟
陈述二。一个人只有一个姐姐- (一种)
- (b)
- (C)
- (d)
- (e)
回答:
(d) if the data even in both Statements I and II together are not sufficient to answer the question.
- 考虑以下短语:
陈述:所有A都是B。
所有B都是D。
没有D是C。
结论:
I.所有A都是C。
二。一些A是C
选择下面给出的正确选项:- 只有结论我是真的。
- 只有结论II是正确的。
- 结论一或结论二是正确的
- 结论一和结论二都不成立
- 结论I和II都是正确的。
回答:
(d)
- 考虑以下短语:
声明: “树林深处只有黑暗,但我有诺言要遵守。”
假设:
I.树林很诱人。
二。一个人必须兑现自己的诺言,而不是去树林里
选择下面给出的正确选项。- 如果仅假设我是隐含的
- 如果仅假设II是隐式的。
- 如果I或II是隐式的。
- 如果I和II都不是隐式的。
- 如果I和II都是隐式的。
回答:
(a)
- 考虑以下短语:
声明:熨斗烫时罢工
假设:
I.我们应该在正确的时间塑造事物。
二。固化后很难成型。
选择下面给出的正确选项。- 如果仅假设我是隐含的
- 如果仅假设II是隐式的。
- 如果I或II是隐式的。
- 如果I和II都不是隐式的。
- 如果I和II都是隐式的。
回答:
(e)
- 声明:
我–有些S是L
II –有些C是P
III –所有P为R
结论:
I.一些P是L
二。一些C是R
选择下面给出的正确选项:- 只有结论我是真的。
- 只有结论II是正确的。
- 结论一或结论二是正确的
- 结论一和结论二都不成立
- 结论I和II都是正确的。
回答:
(d) neither conclusion I nor conclusion II is true
- 找出错误的序列号:3,-15、35、63、99,-143
- -15
- 35
- 63
- 99
回答:
63
解释:
Series: Sn = 1*3 – 3*5 + 5*7 – …
- 依次找到错误的数字:1、8、64、125、216
- 8
- 27
- 64
- 216
回答:
64
解释:
Tn = 13 + 23 + 33 + 43 + …..