N中最右置位形成的数字

给定一个整数N ，任务是找到一个整数M ，该整数是通过取N中最右边的置位而形成的，即M中唯一的置位将是N中最右边的置位，其余的这些位将不被置位。
例子：

Input: N = 7 
Output: 1 
7 = 111, the number formed by the last set bit is 001 i.e. 1.
Input: N = 10 
Output: 2 
10 = 1010 -> 0010 = 2
Input: N = 16 
Output: 16 
 

方法：

• 存储x = n＆(n – 1) ，这将使n中从右开始的第一个置位位置未设置。
• 现在，更新n = n ^ x以设置更改后的位，并取消设置所有其他整数(即所需的整数)。

下面是上述方法的实现：

C++

// C++ implementation of the approach
#include 
using namespace std;
 
// Function to return the integer formed
// by taking the rightmost set bit in n
int firstSetBit(int n)
{
 
    // n & (n - 1) unsets the first set
    // bit from the right in n
    int x = n & (n - 1);
 
    // Take xor with the original number
    // The position of the 'changed bit'
    // will be set and rest will be unset
    return (n ^ x);
}
 
// Driver code
int main()
{
    int n = 12;
 
    cout << firstSetBit(n);
 
    return 0;
}

Java

// Java implementation of the approach
class geeks
{
     
    // Function to return the integer formed
    // by taking the rightmost set bit in n
    public static int firstSetBit(int n)
    {
         
        // n & (n - 1) unsets the first set
        // bit from the right in n
        int x = n & (n-1);
         
        // Take xor with the original number
        // The position of the 'changed bit'
        // will be set and rest will be unset
        return (n ^ x);
    }
     
    // Driver Code
    public static void main (String[] args)
    {
        int n = 12;
        System.out.println(firstSetBit(n));
    }
}
 
// This code is contributed by
// sanjeev2552

Python3

# Python3 implementation of the approach
 
# Function to return the integer formed
# by taking the rightmost set bit in n
def firstSetBit(n):
 
    # n & (n - 1) unsets the first set
    # bit from the right in n
    x = n & (n - 1)
 
    # Take xor with the original number
    # The position of the 'changed bit'
    # will be set and rest will be unset
    return (n ^ x)
 
# Driver code
n = 12
 
print(firstSetBit(n))
 
# This code is contributed by mohit kumar 29

C#

// C# implementation of the approach
using System;
 
class geeks
{
     
    // Function to return the integer formed
    // by taking the rightmost set bit in n
    public static int firstSetBit(int n)
    {
         
        // n & (n - 1) unsets the first set
        // bit from the right in n
        int x = n & (n-1);
         
        // Take xor with the original number
        // The position of the 'changed bit'
        // will be set and rest will be unset
        return (n ^ x);
    }
     
    // Driver Code
    public static void Main ()
    {
        int n = 12;
        Console.WriteLine(firstSetBit(n));
    }
}
 
// This code is contributed by
// anuj_67..

Javascript

// JavaScript implementation of the approach
 
// Function to return the integer formed
// by taking the rightmost set bit in n
function firstSetBit(n)
{
 
    // n & (n - 1) unsets the first set
    // bit from the right in n
    let x = n & (n - 1);
 
    // Take xor with the original number
    // The position of the 'changed bit'
    // will be set and rest will be unset
    return (n ^ x);
}
 
// Driver code
    let n = 12;
    document.write(firstSetBit(n));
 
// This code is contributed by Manoj.

输出：

4