不使用循环和递归的数组元素的总和

给定N个元素的数组，任务是查找N个元素的总和，而无需使用循环(for，while和doWhile)和递归。
例子：

Input: arr[]={1, 2, 3, 4, 5}   
Output: 15

Input: arr[]={10, 20, 30}   
Output: 60

方法：无条件跳转语句可用于解决此问题。
无条件跳转语句：
跳转语句中断了语句的顺序执行，因此执行在程序的另一点继续进行。如果跳转目标超出其范围，则跳转会破坏自动变量。有四种导致C无条件跳转的语句：break，continue，goto和return。
要解决此特定问题，goto语句可能会很有用。
goto声明：
goto语句是一个跳转语句，有时也称为无条件跳转语句。 goto语句可用于从函数的任何位置跳转到任何位置。
语法：

Syntax1      |   Syntax2
----------------------------
goto label;  |    label:  
.                  |    .
.                  |    .
.                  |    .
label:          |    goto label;

在以上语法中，第一行告诉编译器转到或跳到标记为标签的语句。这里label是一个用户定义的标识符，它指示目标语句。 “ label：”之后紧随其后的语句是目标语句。 “标签：”也可以出现在“转到标签”之前；上面语法中的语句。

下面是上述方法的实现：

C++

// C++ program to find the sum of
// N elements with goto statement
 
#include 
using namespace std;
 
// Function to perform desired operation
int operate(int array[], int N)
{
    int sum = 0, index = 0;
 
label:
    sum += array[index++];
 
    if (index < N) {
 
        // backward jump of goto statement
        goto label;
    }
 
    // return the sum
    return sum;
}
 
// Driver Code
int main()
{
 
    // Get N
    int N = 5, sum = 0;
 
    // Input values of an array
    int array[] = { 1, 2, 3, 4, 5 };
 
    // Find the sum
    sum = operate(array, N);
 
    // Print the sum
    cout << sum;
}

C

// C program to find the sum of
// N elements with goto statement
 
#include 
 
// Function to perform desired operation
int operate(int array[], int N)
{
    int sum = 0, index = 0;
 
label:
    sum += array[index++];
 
    if (index < N) {
 
        // backward jump of goto statement
        goto label;
    }
 
    // return the sum
    return sum;
}
 
// Driver Code
int main()
{
 
    // Get N
    int N = 5, sum = 0;
 
    // Input values of an array
    int array[] = { 1, 2, 3, 4, 5 };
 
    // Find the sum
    sum = operate(array, N);
 
    // Print the sum
    printf("%d", sum);
}

Java

// Java program to find the sum of
// N elements
class GFG
{
  // Function to perform desired operation
  static int operate(int array[], int N)
  {
    int sum = 0, index = 0;      
    while(true)
    {
      sum += array[index++];      
      if (index < N)
      {
 
        // backward jump of goto statement
        continue;
      }
      else
      {
        break;
      }
    }
 
    // return the sum
    return sum;
  }
 
  // Driver code
  public static void main(String[] args)
  {
 
    // Get N
    int N = 5, sum = 0;
 
    // Input values of an array
    int array[] = { 1, 2, 3, 4, 5 };
 
    // Find the sum
    sum = operate(array, N);
 
    // Print the sum
    System.out.print(sum);
  }
}
 
// This code is contributed by divyeshrabaiya07

Python3

# Python3 program to find the sum of
# N elements
 
# Function to perform desired operation
def operate(array, N) :  
    Sum, index = 0, 0  
    while(True) :
        Sum += array[index]
        index += 1
        if index < N :
           
            # backward jump of goto statement
            continue
        else :
            break
         
    # return the sum
    return Sum
     
# Get N
N, Sum = 5, 0
 
# Input values of an array
array = [ 1, 2, 3, 4, 5 ]
 
# Find the sum
Sum = operate(array, N)
 
# Print the sum
print(Sum)
 
# This code is contributed by divyesh072019

C#

// C# program to find the sum of
// N elements with goto statement
using System;
 
class GFG
{
// Function to perform desired operation
static int operate(int[] array, int N)
{
    int sum = 0, index = 0;
 
label:
    sum += array[index++];
 
    if (index < N)
    {
 
        // backward jump of goto statement
        goto label;
    }
 
    // return the sum
    return sum;
}
 
// Driver Code
public static void Main()
{
 
    // Get N
    int N = 5, sum = 0;
 
    // Input values of an array
    int[] array = { 1, 2, 3, 4, 5 };
 
    // Find the sum
    sum = operate(array, N);
 
    // Print the sum
    Console.Write(sum);
}
}
 
// This code is contributed
// by Akanksha Rai

Javascript

    // Javascript program to find the sum of
    // N elements
     
    // Function to perform desired operation
    function operate(array, N)
    {
      let sum = 0, index = 0;     
      while(true)
      {
        sum += array[index++];     
        if (index < N)
        {
 
          // backward jump of goto statement
          continue;
        }
        else
        {
          break;
        }
      }
 
      // return the sum
      return sum;
    }
       
    // Get N
    let N = 5, sum = 0;
  
    // Input values of an array
    let array = [ 1, 2, 3, 4, 5 ];
  
    // Find the sum
    sum = operate(array, N);
  
    // Print the sum
    document.write(sum);
     
    // This code is contributed by suresh07.

输出：

15

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