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📜  程序找到系列9、23、45、75、113的N个术语。

📅  最后修改于: 2021-05-30 15:00:08             🧑  作者: Mango

给定数字N,任务是在给定系列中找到第N个项:

9, 23, 45, 75, 113, 159......

例子:

Input: 4
Output: 113
Explanation:
For N = 4
Nth term = ( 2 * N + 3 )*( 2 * N + 3 ) - 2 * N
         = ( 2 * 4 + 3 )*( 2 * 4 + 3 ) - 2 * 4
         = 113

Input: 10
Output: 509

方法:
给定级数的N个项可以概括为:

Nth term of the series : ( 2 * N + 3 )*( 2 * N + 3 ) - 2 * N

下面是上述问题的实现:
程序:

C++
// CPP program to find N-th term of the series:
// 9, 23, 45, 75, 113...
 
#include 
using namespace std;
 
// calculate Nth term of series
int nthTerm(int N)
{
    return (2 * N + 3) * (2 * N + 3) - 2 * N;
}
 
// Driver Function
int main()
{
 
    // Get the value of N
    int N = 4;
 
    // Find the Nth term
    // and print it
    cout << nthTerm(N);
 
    return 0;
}


Java
// Java program to find
// N-th term of the series:
// 9, 23, 45, 75, 113...
 
class GFG
{
 
// calculate Nth term of series
static int nthTerm(int N)
{
    return (2 * N + 3) *
           (2 * N + 3) - 2 * N;
}
 
// Driver code
public static void main(String[] args)
{
     
    // Get the value of N
    int N = 4;
     
    // Find the Nth term
    // and print it
    System.out.println(nthTerm(N));
}
}
 
// This code is contributed by Bilal


Python3
# Python program to find
# N-th term of the series:
# 9, 23, 45, 75, 113...
def nthTerm(N):
     
    # calculate Nth term of series
    return ((2 * N + 3) *
            (2 * N + 3) - 2 * N);
 
# Driver Code
 
# Get the value of N
n = 4
 
# Find the Nth term
# and print it
print(nthTerm(n))
 
# This code is contributed by Bilal


C#
// C# program to find
// N-th term of the series:
// 9, 23, 45, 75, 113...
using System;
 
class GFG
{
 
// calculate Nth term of series
static int nthTerm(int N)
{
    return (2 * N + 3) *
           (2 * N + 3) - 2 * N;
}
 
// Driver code
public static void Main()
{
     
    // Get the value of N
    int N = 4;
     
    // Find the Nth term
    // and print it
    Console.WriteLine(nthTerm(N));
}
}
 
// This code is contributed
// by Akanksha Rai(Abby_akku)


PHP


Javascript


输出:
113

时间复杂度: O(1)