< type_traits >头文件中提供了C++ STL的std :: is_nothrow_assignable模板。 C++ STL的std :: is_nothrow_assignable模板用于检查A是否可分配给B类型,并且众所周知它不会引发任何异常。如果A是可分配给B的类型,则返回布尔值true,否则返回false。
头文件:
#include
模板类别:
template< class A, class B >
struct is_nothrow_assignable;
句法:
std::is_assignable::value
参数:模板std :: is_assignable接受以下参数:
- A:它代表参数B被隐式分配的参数。
- B:表示可分配给A的参数类型。
返回值:模板std :: is_assignable返回一个布尔变量,如下所示:
- 正确:如果类型A可分配给类型B。
- False:如果类型A不可分配给类型B。
下面是演示C++中std :: is_nothrow_assignable模板的程序:
程序:
// C++ program to illustrate
// std::is_nothrow_assignable
#include
#include
using namespace std;
// Declare structures
struct A {
};
struct B {
B& operator=(const A&) noexcept
{
return *this;
}
B& operator=(const B&)
{
return *this;
}
};
// Declare classes
class GfG {
};
class gfg {
};
enum class AB : int { x,
y,
z };
// Driver Code
int main()
{
cout << boolalpha;
// Check if int& is assignable to
// double or not
cout << "is int = double? "
<< is_nothrow_assignable::value
<< endl;
// Check if struct A is assignable to
// srtuct A or not
cout << "is struct A = struct A? "
<< is_nothrow_assignable::value
<< endl;
// Check if struct B is assignable to
// srtuct A or not
cout << "is class B = class A? "
<< is_nothrow_assignable::value
<< endl;
// Check if struct B is assignable to
// srtuct B or not
cout << "is class B = class B? "
<< is_nothrow_assignable::value
<< endl;
// Check if enum class AB is assignable
// from class gfg or not
cout << "is class AB = class gfg? "
<< is_nothrow_assignable::value
<< endl;
// Check if class GfG assignable to
// class gfg or not
cout << "is class Gfg = class gfg? "
<< is_nothrow_assignable::value
<< endl;
return 0;
}
输出:
is int = double? true
is struct A = struct A? true
is class B = class A? true
is class B = class B? false
is class AB = class gfg? false
is class Gfg = class gfg? false
参考: http://www.cplusplus.com/reference/type_traits/is_nothrow_assignable/
要从最佳影片策划和实践问题去学习,检查了C++基础课程为基础,以先进的C++和C++ STL课程基础加上STL。要完成从学习语言到DS Algo等的更多准备工作,请参阅“完整面试准备课程” 。