📅  最后修改于: 2020-10-15 06:22:43             🧑  作者: Mango
在此程序中,我们创建一个循环链接列表并在列表中搜索一个节点。
9-> 5-> 2-> 7-> 3
考虑上面的例子。假设我们需要搜索节点5。要解决此问题,我们将遍历列表并将每个节点与5进行比较。如果找到匹配项,则将标志设置为true,并打印出节点5的位置。在此示例中,节点5位于位置2。
#Represents the node of list.
class Node:
def __init__(self,data):
self.data = data;
self.next = None;
class CreateList:
#Declaring head and tail pointer as null.
def __init__(self):
self.head = Node(None);
self.tail = Node(None);
self.head.next = self.tail;
self.tail.next = self.head;
#This function will add the new node at the end of the list.
def add(self,data):
newNode = Node(data);
#Checks if the list is empty.
if self.head.data is None:
#If list is empty, both head and tail would point to new node.
self.head = newNode;
self.tail = newNode;
newNode.next = self.head;
else:
#tail will point to new node.
self.tail.next = newNode;
#New node will become new tail.
self.tail = newNode;
#Since, it is circular linked list tail will point to head.
self.tail.next = self.head;
#Searches for a node in the list
def search(self,element):
current = self.head;
i = 1;
flag = False;
#Checks whether list is empty
if(self.head == None):
print("List is empty");
else:
while(True):
#Compares element to be found with each node present in the list
if(current.data == element):
flag = True;
break;
current = current.next;
i = i + 1;
if(current == self.head):
break;
if(flag):
print("Element is present in the list at the position : " + str(i));
else:
print("Element is not present in the list");
class CircularLinkedList:
cl = CreateList();
#Adds data to the list
cl.add(1);
cl.add(2);
cl.add(3);
cl.add(4);
#Search for node 2 in the list
cl.search(2);
#Search for node in the list
cl.search(7);
输出:
Element is present in the list at the position : 2
Element is not present in the list
#include
#include
#include
#include
//Represents the node of list.
struct node{
int data;
struct node *next;
};
//Declaring head and tail pointer as null.
struct node *head = NULL;
struct node *tail = NULL;
//This function will add the new node at the end of the list.
void add(int data){
//Create new node
struct node *newNode = (struct node*)malloc(sizeof(struct node));
newNode->data = data;
//Checks if the list is empty.
if(head == NULL){
//If list is empty, both head and tail would point to new node.
head = newNode;
tail = newNode;
newNode->next = head;
}else {
//tail will point to new node.
tail->next = newNode;
//New node will become new tail.
tail = newNode;
//Since, it is circular linked list tail will point to head.
tail->next = head;
}
}
//Searches for a node in the list
void search(int element) {
struct node *current = head;
int i = 1;
bool flag = false;
//Checks whether list is empty
if(head == NULL) {
printf("List is empty");
}
else {
do{
//Compares element to be found with each node present in the list
if(current->data == element) {
flag = true;
break;
}
current = current->next;
i++;
}while(current != head);
if(flag)
printf("Element is present in the list at the position : %d", i);
else
printf("\nElement is not present in the list");
}
}
int main()
{
//Adds data to the list
add(1);
add(2);
add(3);
add(4);
//Search for node 2 in the list
search(2);
//Search for node in the list
search(7);
return 0;
}
输出:
Element is present in the list at the position : 2
Element is not present in the list
public class SearchNode {
//Represents the node of list.
public class Node{
int data;
Node next;
public Node(int data) {
this.data = data;
}
}
//Declaring head and tail pointer as null.
public Node head = null;
public Node tail = null;
//This function will add the new node at the end of the list.
public void add(int data){
//Create new node
Node newNode = new Node(data);
//Checks if the list is empty.
if(head == null) {
//If list is empty, both head and tail would point to new node.
head = newNode;
tail = newNode;
newNode.next = head;
}
else {
//tail will point to new node.
tail.next = newNode;
//New node will become new tail.
tail = newNode;
//Since, it is circular linked list tail will point to head.
tail.next = head;
}
}
//Searches for a node in the list
public void search(int element) {
Node current = head;
int i = 1;
boolean flag = false;
//Checks whether list is empty
if(head == null) {
System.out.println("List is empty");
}
else {
do{
//Compares element to be found with each node present in the list
if(current.data == element) {
flag = true;
break;
}
current = current.next;
i++;
}while(current != head);
if(flag)
System.out.println("Element is present in the list at the position : " + i);
else
System.out.println("Element is not present in the list");
}
}
public static void main(String[] args) {
SearchNode cl = new SearchNode();
//Adds data to the list
cl.add(1);
cl.add(2);
cl.add(3);
cl.add(4);
//Search for node 2 in the list
cl.search(2);
//Search for node in the list
cl.search(7);
}
}
输出:
Element is present in the list at the position : 2
Element is not present in the list
using System;
namespace CircularLinkedList
{
public class Program
{
//Represents the node of list.
public class Node{
public T data;
public Node next;
public Node(T value) {
data = value;
next = null;
}
}
public class CreateList{
protected Node head = null;
protected Node tail = null;
//This function will add the new node at the end of the list.
public void add(T data){
//Create new node
Node newNode = new Node(data);
//Checks if the list is empty.
if(head == null){
head = newNode;
tail = newNode;
newNode.next = head;
}else{
//tail will point to new node.
tail.next = newNode;
//New node will become new tail.
tail = newNode;
//Since, it is circular linked list tail will point to head.
tail.next = head;
}
}
//Searches for a node in the list
public void search(T element) {
Node current = head;
int i = 1;
bool flag = false;
//Checks whether list is empty
if(head == null) {
Console.WriteLine("List is empty");
}
else {
do{
//Compares element to be found with each node present in the list
if(current.data.Equals(element)) {
flag = true;
break;
}
current = current.next;
i++;
}while(current != head);
if(flag)
Console.WriteLine("Element is present in the list at the position : " + i);
else
Console.WriteLine("Element is not present in the list");
}
}
}
public static void Main()
{
CreateList cl = new CreateList();
//Adds data to the list
cl.add(1);
cl.add(2);
cl.add(3);
cl.add(4);
//Search for node 2 in the list
cl.search(2);
//Search for node in the list
cl.search(7);
}
}
}
输出:
Element is present in the list at the position : 2
Element is not present in the list
data = $data;
$this->next = NULL;
}
}
class CreateList{
//Declaring head and tail pointer as null.
private $head;
private $tail;
function __construct(){
$this->head = NULL;
$this->tail = NULL;
}
//This function will add the new node at the end of the list.
function add($data){
//Create new node
$newNode = new Node($data);
//Checks if the list is empty.
if($this->head == NULL){
//If list is empty, both head and tail would point to new node.
$this->head = $newNode;
$this->tail = $newNode;
$newNode->next = $this->head;
}
else{
//tail will point to new node.
$this->tail->next = $newNode;
//New node will become new tail.
$this->tail = $newNode;
//Since, it is circular linked list tail will point to head.
$this->tail->next = $this->head;
}
}
//Searches for a node in the list
function search($element) {
$current = $this->head;
$i = 1;
$flag = false;
//Checks whether list is empty
if($this->head == NULL) {
echo "List is empty";
}
else {
do{
//Compares element to be found with each node present in the list
if($current->data == $element) {
$flag = true;
break;
}
$current = $current->next;
$i++;
}while($current != $this->head);
if($flag)
echo "Element is present in the list at the position : $i
";
else
echo "Element is not present in the list
";
}
}
}
$cl = new CreateList();
//Adds data to the list
$cl->add(1);
$cl->add(2);
$cl->add(3);
$cl->add(4);
//Search for node 2 in the list
$cl->search(2);
//Search for node in the list
$cl->search(7);
?>
输出:
Element is present in the list at the position : 2
Element is not present in the list