给定一个字符串S ，任务是检查该字符串是否可以仅使用 qwerty 键盘的单行输入。
例子：
Input: S = “Dad”
Output: Yes
Explanation:
Characters “D” and “a” are present in the same row of qwerty keypad. That is second Row.
Input: S = “Mom”
Output: No
Explanation:
Characters “M” and “o” are not present in the same row of qwerty keypad.
方法：想法是将 qwerty 键盘同一行的字符存储到不同的哈希映射中，以检查字符串的所有字符是否来自同一行。
下面是上述方法的实现：
C++
// C++ Program to check whether
// the string can be printed
// using same row of qwerty keypad
#include
using namespace std;
// Function to find the row of the
// character in the qwerty keypad
int checkQwertyRow(char x)
{
// Sets to include the characters
// from the same row of the qwerty keypad
set first_row
= { '1', '2', '3', '4',
'5', '6', '7', '8',
'9', '0', '-', '=' };
set second_row
= { 'Q', 'W', 'E', 'R', 'T',
'Y', 'U', 'I', 'O', 'P',
'[', ']', 'q', 'w', 'e',
'r', 't', 'y', 'u', 'i',
'o', 'p' };
set third_row
= { 'A', 'S', 'D', 'F', 'G',
'H', 'J', 'K', 'L', ';',
':', 'a', 's', 'd', 'f',
'g', 'h', 'j', 'k', 'l' };
set fourth_row
= { 'Z', 'X', 'C', 'V', 'B',
'N', 'M', ',', '.',
'/', 'z', 'x', 'c', 'v',
'b', 'n', 'm' };
// Condition to check the row of the
// current character of the string
if (first_row.count(x) > 0) {
return 1;
}
else if (second_row.count(x) > 0) {
return 2;
}
else if (third_row.count(x) > 0) {
return 3;
}
else if (fourth_row.count(x) > 0) {
return 4;
}
return 0;
}
// Function to check the characters are
// from the same row of the qwerty keypad
bool checkValidity(string str)
{
char x = str[0];
int row = checkQwertyRow(x);
for (int i = 0; i < str.length(); i++) {
x = str[i];
if (row != checkQwertyRow(x)) {
return false;
}
}
return true;
}
// Driver Code
int main()
{
string str = "GeeksforGeeks";
if (checkValidity(str))
cout << "Yes";
else
cout << "No";
return (0);
} Java
// Java program to check whether
// the string can be printed
// using same row of qwerty keypad
import java.util.*;
class GFG{
// Function to find the row of the
// character in the qwerty keypad
static int checkQwertyRow(char x)
{
// Sets to include the characters
// from the same row of the qwerty keypad
Character[] first_row1 = { '1', '2', '3', '4',
'5', '6', '7', '8',
'9', '0', '-', '=' };
Set first_row = new HashSet<>(
Arrays.asList(first_row1));
Character[] second_row1 = { 'Q', 'W', 'E', 'R', 'T',
'Y', 'U', 'I', 'O', 'P',
'[', ']', 'q', 'w', 'e',
'r', 't', 'y', 'u', 'i',
'o', 'p' };
Set second_row = new HashSet<>(
Arrays.asList(second_row1));
Character[] third_row1 = { 'A', 'S', 'D', 'F', 'G',
'H', 'J', 'K', 'L', ';',
':', 'a', 's', 'd', 'f',
'g', 'h', 'j', 'k', 'l' };
Set third_row = new HashSet<>(
Arrays.asList(third_row1));
Character[] fourth_row1 = { 'Z', 'X', 'C', 'V', 'B',
'N', 'M', ',', '.',
'/', 'z', 'x', 'c', 'v',
'b', 'n', 'm' };
Set fourth_row = new HashSet<>(
Arrays.asList(fourth_row1));
// Condition to check the row of the
// current character of the string
if (first_row.contains(x))
{
return 1;
}
else if (second_row.contains(x))
{
return 2;
}
else if (third_row.contains(x))
{
return 3;
}
else if (fourth_row.contains(x))
{
return 4;
}
return 0;
}
// Function to check the characters are
// from the same row of the qwerty keypad
static boolean checkValidity(String str)
{
char x = str.charAt(0);
int row = checkQwertyRow(x);
for(int i = 0; i < str.length(); i++)
{
x = str.charAt(i);
if (row != checkQwertyRow(x))
{
return false;
}
}
return true;
}
// Driver code
public static void main(String[] args)
{
String str = "GeeksforGeeks";
if (checkValidity(str))
System.out.println("Yes");
else
System.out.println("No");
}
}
// This code is contributed by offbeat Python3
# Python3 program to check whether
# the string can be printed
# using same row of qwerty keypad
# Function to find the row of the
# character in the qwerty keypad
def checkQwertyRow(x):
# Sets to include the
# characters from the
# same row of the qwerty keypad
first_row = ['1', '2', '3', '4',
'5', '6', '7', '8',
'9', '0', '-', '=']
second_row = ['Q', 'W', 'E', 'R',
'T', 'Y', 'U', 'I',
'O', 'P', '[', ']',
'q', 'w', 'e', 'r',
't', 'y', 'u', 'i',
'o', 'p']
third_row = ['A', 'S', 'D', 'F',
'G', 'H', 'J', 'K',
'L', ';', ':', 'a',
's', 'd', 'f', 'g',
'h', 'j', 'k', 'l']
fourth_row = ['Z', 'X', 'C', 'V',
'B', 'N', 'M', ',',
'.', '/', 'z', 'x',
'c', 'v', 'b', 'n', 'm']
# Condition to check the
# row of the current character
# of the string
if(first_row.count(x) > 0):
return 1
elif(second_row.count(x) > 0):
return 2
elif(third_row.count(x) > 0):
return 3
elif(fourth_row.count(x) > 0):
return 4
return 0
# Function to check the
# characters are from the
# same row of the qwerty keypad
def checkValidity(str):
x = str[0]
row = checkQwertyRow(x)
for i in range(len(str)):
x = str[i]
if(row != checkQwertyRow(x)):
return False
return True
# Driver Code
str = "GeeksforGeeks"
if(checkValidity(str)):
print("Yes")
else:
print("No")
# This code is contributed by avanitrachhadiya2155C#
// C# program to check whether
// the string can be printed
// using same row of qwerty keypad
using System;
using System.Collections.Generic;
class GFG{
// Function to find the row of the
// character in the qwerty keypad
static int checkQwertyRow(char x)
{
// Sets to include the characters
// from the same row of the qwerty keypad
char[] first_row1 = { '1', '2', '3', '4',
'5', '6', '7', '8',
'9', '0', '-', '=' };
HashSet first_row = new HashSet(
first_row1);
char[] second_row1 = { 'Q', 'W', 'E', 'R', 'T',
'Y', 'U', 'I', 'O', 'P',
'[', ']', 'q', 'w', 'e',
'r', 't', 'y', 'u', 'i',
'o', 'p' };
HashSet second_row = new HashSet(
second_row1);
char[] third_row1 = { 'A', 'S', 'D', 'F', 'G',
'H', 'J', 'K', 'L', ';',
':', 'a', 's', 'd', 'f',
'g', 'h', 'j', 'k', 'l' };
HashSet third_row = new HashSet(
third_row1);
char[] fourth_row1 = { 'Z', 'X', 'C', 'V', 'B',
'N', 'M', ',', '.', '/',
'z', 'x', 'c', 'v', 'b',
'n', 'm' };
HashSet fourth_row = new HashSet(
fourth_row1);
// Condition to check the row of the
// current character of the string
if (first_row.Contains(x))
{
return 1;
}
else if (second_row.Contains(x))
{
return 2;
}
else if (third_row.Contains(x))
{
return 3;
}
else if (fourth_row.Contains(x))
{
return 4;
}
return 0;
}
// Function to check the characters are
// from the same row of the qwerty keypad
static bool checkValidity(String str)
{
char x = str[0];
int row = checkQwertyRow(x);
for(int i = 0; i < str.Length; i++)
{
x = str[i];
if (row != checkQwertyRow(x))
{
return false;
}
}
return true;
}
// Driver code
public static void Main(String[] args)
{
String str = "GeeksforGeeks";
if (checkValidity(str))
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
// This code is contributed by Amit Katiyar 输出：
No
时间复杂度： O(N)
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