Java中的 CompositeName compareTo() 方法及示例

javax.naming.CompositeName 类的compareTo()方法用于将此 CompositeName 与作为参数传递的指定对象进行比较。它返回负整数、零或正整数，因为此 CompositeName 小于、等于或大于作为参数的给定 Object。如果传递的对象为 null 或不是 CompositeName 的实例，则此方法会抛出 ClassCastException。

句法：

public int compareTo(Object obj)

参数：此方法接受obj ，它是要比较的非空对象。

返回值：此方法返回负整数、零或正整数，因为此 Name 小于、等于或大于给定 Object。

例外：
如果 obj 不是 CompositeName，则此方法抛出 ClassCastException。

下面的程序说明了 CompositeName.compareTo() 方法：
方案一：

// Java program to demonstrate
// CompositeName.compareTo()
  
import javax.naming.CompositeName;
import javax.naming.InvalidNameException;
  
public class GFG {
    public static void main(String[] args)
        throws InvalidNameException
    {
  
        // create Composite name object
        CompositeName compositeName1
            = new CompositeName("x/y");
        CompositeName compositeName2
            = new CompositeName("x/z");
  
        // apply compareTo()
        int value
            = compositeName1.compareTo(compositeName2);
  
        // print value
        if (value > 0)
            System.out.println("CompositeName1 is "
                               + "greater than CompositeName2");
        else if (value < 0)
            System.out.println("CompositeName1 is "
                               + "smaller than CompositeName2");
        else
            System.out.println("CompositeName1 is "
                               + " equal to CompositeName2");
    }
}

输出：

CompositeName1 is smaller than CompositeName2

方案二：

// Java program to demonstrate
// CompositeName.compareTo() method
  
import javax.naming.CompositeName;
import javax.naming.InvalidNameException;
  
public class GFG {
    public static void main(String[] args)
        throws InvalidNameException
    {
  
        // create Composite name object
        CompositeName compositeName1
            = new CompositeName("x/y/z/a");
        CompositeName compositeName2
            = new CompositeName("x/y/x/a");
  
        // apply compareTo()
        int value
            = compositeName1.compareTo(compositeName2);
  
        // print value
        if (value > 0)
            System.out.println("CompositeName1 is "
                               + "greater than CompositeName2");
        else if (value < 0)
            System.out.println("CompositeName1 is "
                               + "smaller than CompositeName2");
        else
            System.out.println("CompositeName1 is "
                               + " equal to CompositeName2");
    }
}

输出：

CompositeName1 is greater than CompositeName2

参考资料：https://docs.oracle.com/javase/10/docs/api/javax/naming/CompositeName.html#compareTo(Java.lang.Object)