Java中的 CompoundName compareTo() 方法和示例

Java中的 CompoundName compareTo() 方法及示例

javax.naming.CompoundName 类的compareTo()方法用于将此 CompoundName 与作为参数传递的指定对象进行比较。它返回一个负整数、零或正整数，因为此 CompoundName 对象小于、等于或大于作为参数的给定对象。如果传递的对象为 null 或不是 CompoundName 的实例，则此方法会抛出 ClassCastException。

句法：

public int compareTo(Object obj)

参数：此方法接受obj ，它是要比较的非空对象。

返回值：此方法返回负整数、零或正整数，因为此 Name 小于、等于或大于给定 Object。

异常：如果传递的 obj 不是 CompoundName 对象，此方法将抛出ClassCastException 。

下面的程序说明了 CompoundName.compareTo() 方法：
方案一：

// Java program to demonstrate
// CompoundName.compareTo()
  
import java.util.Properties;
import javax.naming.CompoundName;
import javax.naming.InvalidNameException;
  
public class GFG {
    public static void main(String[] args)
        throws InvalidNameException
    {
  
        // need properties for CompoundName
        Properties props = new Properties();
        props.put("jndi.syntax.separator", ":");
        props.put("jndi.syntax.direction",
                  "left_to_right");
  
        // create compound name object
        CompoundName CompoundName1
            = new CompoundName("x:y:z",
                               props);
        CompoundName CompoundName2
            = new CompoundName("x:y:m",
                               props);
  
        // apply compareTo()
        int value
            = CompoundName1
                  .compareTo(CompoundName2);
  
        // print value
        if (value > 0)
            System.out.println(
                "CompoundName1 is "
                + "greater than CompoundName2");
        else if (value < 0)
            System.out.println(
                "CompoundName1 is "
                + "smaller than CompoundName2");
        else
            System.out.println(
                "CompoundName1 is "
                + "equal to CompoundName2");
    }
}

输出：

CompoundName1 is greater than CompoundName2

方案二：

// Java program to demonstrate
// CompoundName.compareTo() method
  
import java.util.Properties;
import javax.naming.CompoundName;
import javax.naming.InvalidNameException;
  
public class GFG {
    public static void main(String[] args)
        throws InvalidNameException
    {
  
        // need properties for CompoundName
        Properties props = new Properties();
        props.put("jndi.syntax.separator", "@");
        props.put("jndi.syntax.direction",
                  "left_to_right");
  
        // create compound name object
        CompoundName CompoundName1
            = new CompoundName(
                "x@y@z@M@n",
                props);
        CompoundName CompoundName2
            = new CompoundName(
                "x@y@z@M@n",
                props);
  
        // apply compareTo()
        int value
            = CompoundName1
                  .compareTo(CompoundName2);
  
        // print value
        if (value > 0)
            System.out.println(
                "CompoundName1 is "
                + "greater than CompoundName2");
        else if (value < 0)
            System.out.println(
                "CompoundName1 is "
                + "smaller than CompoundName2");
        else
            System.out.println(
                "CompoundName1 is "
                + "equal to CompoundName2");
    }
}

输出：

CompoundName1 is equal to CompoundName2

参考：https://docs.oracle.com/javase/10/docs/api/javax/naming/CompoundName.html#compareTo(Java.lang.Object)