Python|测试列表元素相似度

给定一个列表，您的任务是确定该列表是否相同 K%，即元素的填充次数超过 K%。下面给出了一些解决任务的方法。
方法 #1 使用 collections.Counter

# Python3 code to demonstrate
# to check whether the list
# K percent same or not
from collections import Counter
  
# initializing list
ini_list1 = [1, 2, 3, 1, 1, 1, 1, 1, 3, 2]
  
# printing initial list
print ("Initial list", ini_list1)
  
# initializing K
K = 60
  
# code to check whether list is K % same or not
i, freq = Counter(ini_list1).most_common(1)[0]
  
if len(ini_list1)*(K / 100) <= freq:
    print("True")
else:
    print("False")

输出：

Initial list [1, 2, 3, 1, 1, 1, 1, 1, 3, 2] 
True

方法#2：使用字典及其值

# Python3 code to demonstrate
# to check whether the list
# K percent same or not
from collections import Counter, defaultdict
  
# initializing list
ini_list1 = [1, 2, 3, 1, 1, 1, 1, 1, 3, 2]
  
# printing initial list
print ("Initial list", ini_list1)
  
# initializing K
K = 60
  
# code to check whether list is K % same or not
freq = defaultdict(int)
for x in ini_list1:
    freq[x] += 1
freq = freq.values()
if max(freq) >= (K / 100) * sum(freq):
    print ("True")
else:
    print ("False")

输出：

initial list [1, 2, 3, 1, 1, 1, 1, 1, 1, 1]
True