Python - 测试行是否具有相似的频率

在本文中，我们有一个给定的矩阵，测试是否所有行都有相似的元素。

Input : test_list = [[6, 4, 2, 7, 3], [7, 3, 6, 4, 2], [2, 4, 7, 3, 6]] 
Output : True 
Explanation : All lists have 2, 3, 4, 6, 7.
Input : test_list = [[6, 4, 2, 7, 3], [7, 5, 6, 4, 2], [2, 4, 7, 3, 6]] 
Output : False 
Explanation : 2nd list has 5 instead of 3. 

方法 #1：使用 Counter() + 列表理解

在这里，我们使用 Counter() 计算元素的频率字典，并与 Matrix 中的每一行进行比较，如果它们检出则返回 True。

Python3

# Python3 code to demonstrate working of 
# Test if Rows have Similar frequency
# Using Counter() + list comprehension
from collections import Counter
  
# initializing list
test_list = [[6, 4, 2, 7, 3], [7, 3, 6, 4, 2], [2, 4, 7, 3, 6]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# checking if all rows are similar 
res = all(dict(Counter(row)) == dict(Counter(test_list[0])) for row in test_list)
  
# printing result 
print("Are all rows similar : " + str(res))

输出

The original list is : [[6, 4, 2, 7, 3], [7, 3, 6, 4, 2], [2, 4, 7, 3, 6]]
Are all rows similar : True

方法 #2：使用列表推导 + sorted() + all()

在这里，我们使用 sorted() 检查相似元素，通过将所有元素排序为排序格式。

蟒蛇3

# Python3 code to demonstrate working of 
# Test if Rows have Similar frequency
# Using list comprehension + sorted() + all()
  
# initializing list
test_list = [[6, 4, 2, 7, 3], [7, 3, 6, 4, 2], [2, 4, 7, 3, 6]]
  
# printing original list
print("The original list is : " + str(test_list))
  
# checking if all rows are similar 
# ordering each row to test 
res = all(list(sorted(row)) == list(sorted(test_list[0])) for row in test_list)
  
# printing result 
print("Are all rows similar : " + str(res))

输出

The original list is : [[6, 4, 2, 7, 3], [7, 3, 6, 4, 2], [2, 4, 7, 3, 6]]
Are all rows similar : True