📅  最后修改于: 2022-03-11 14:45:29.894000             🧑  作者: Mango
x = sc.parallelize([("a", 1), ("b", 4)])
y = sc.parallelize([("a", 2)])
sorted(y.rightOuterJoin(x).collect())
# [('a', (2, 1)), ('b', (None, 4))]