📅  最后修改于: 2022-03-11 14:47:20.747000             🧑  作者: Mango
x = sc.parallelize([("a", 1), ("b", 4)])
y = sc.parallelize([("a", 2), ("a", 3)])
sorted(x.join(y).collect())
# [('a', (1, 2)), ('a', (1, 3))]