C ++程序检查是否可以通过将另一个字符串旋转2个位置来获得一个字符串

给定两个字符串，任务是找出是否可以通过将另一个字符串旋转两个位置来获得一个字符串。

例子：

Input: string1 = “amazon”, string2 = “azonam”
Output: Yes
// rotated anti-clockwise
Input: string1 = “amazon”, string2 = “onamaz”
Output: Yes
// rotated clockwise

编程需要懂一点英语

提问：亚马逊面试

1- There can be only two cases:
    a) Clockwise rotated
    b) Anti-clockwise rotated

2- If clockwise rotated that means elements
   are shifted in right.
   So, check if a substring[2.... len-1] of 
   string2 when concatenated with substring[0,1]
   of string2 is equal to string1. Then, return true.

3- Else, check if it is rotated anti-clockwise 
   that means elements are shifted to left.
   So, check if concatenation of substring[len-2, len-1]
   with substring[0....len-3] makes it equals to
   string1. Then return true.

4- Else, return false.

下面是上述方法的实现。

C++

// C++ program to check if a string 
// is two time rotation of another string.
#include
using namespace std;
  
// Function to check if string2 is 
// obtained by string 1
bool isRotated(string str1, 
               string str2)
{
    if (str1.length() != str2.length())
        return false;
    if(str1.length()<2){
      return str1.compare(str2) == 0;
    }
    string clock_rot = "";
    string anticlock_rot = "";
    int len = str2.length();
  
    // Initialize string as anti-clockwise 
    // rotation
    anticlock_rot = anticlock_rot +
                    str2.substr(len-2, 2) +
                    str2.substr(0, len-2) ;
  
    // Initialize string as clock wise 
    // rotation
    clock_rot = clock_rot +
                str2.substr(2) +
                str2.substr(0, 2) ;
  
    // check if any of them is equal 
    // to string1
    return (str1.compare(clock_rot) == 0 ||
            str1.compare(anticlock_rot) == 0);
}
  
// Driver code
int main()
{
    string str1 = "geeks";
    string str2 = "eksge";
  
    isRotated(str1, str2) ? cout << "Yes"
                          : cout << "No";
    return 0;
}

输出：

Yes

请参阅完整的文章检查是否可以通过将另一个字符串旋转 2 个位置来获得一个字符串以获取更多详细信息！