Python中的 numpy.iscomplex()

numpy.iscomplex()函数逐元素测试它是否是复数（不是无穷大或不是不是数字），并将结果作为布尔数组返回。句法 ：

numpy.iscomplex(array)

参数 ：

array : [array_like] Input array whose element we want to test

返回 ：

boolean array containing the result

代码 1：

Python

# Python Program illustrating
# numpy.iscomplex() method
  
import numpy as geek
 
print("Is Complex : ", geek.iscomplex([1+1j, 1+0j]), "\n")
 
print("Is Complex : ", geek.iscomplex([0+1j, 0]), "\n")

输出 ：

Is Complex :  [ True False] 

Is Complex :  [ True False] 

代码 2：

Python

# Python Program illustrating
# numpy.iscomplex() method
   
import numpy as geek
  
# Returns True/False value for each element
a = geek.arange(20).reshape(5, 4)
print("Is complex : \n", geek.iscomplex(a))
  
# Returns True/False value as ans
# because we have mentioned dtpe in the beginning
b = geek.arange(20).reshape(5, 4).dtype = complex
                
print("\n",b)
print("\nIs complex : ", geek.iscomplex(b))
 
 
b = [[1j],
     [3]]
print("\nIs complex : \n", geek.iscomplex(b))

输出 ：

Is complex : 
 [[False False False False]
 [False False False False]
 [False False False False]
 [False False False False]
 [False False False False]]

Is complex :  False

Is complex : 
 [[ True]
 [False]]

参考： https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.isfinite.html

注意：这些代码不会在在线 IDE 上运行。因此，请在您的系统上运行它们以探索其工作原理。